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ella [17]
3 years ago
5

A cylinder has a radius of 10cm and a height of 9cm. A cone has a radius of 10cm and a height of 9 cm. Show that the volume of t

he cylinder is three times the volume of the cone.
Mathematics
1 answer:
nlexa [21]3 years ago
8 0

Answer:

The answer in the procedure

Step-by-step explanation:

step 1

Find the volume of the cylinder

The volume of the cylinder is equal to

V=\pi r^{2} h

we have

r=10\ cm

h=9\ cm

substitute

V=\pi (10)^{2}(9)=900\pi\ cm^{2}  

step 2

Find the volume of the cone

The volume of the cone is equal to

V=(1/3)\pi r^{2} h

we have

r=10\ cm

h=9\ cm

substitute

V=(1/3)\pi (10)^{2}(9)=300\pi\ cm^{2}  

therefore

we have

Vcylinder=900\pi\ cm^{2}  

Vcone=300\pi\ cm^{2}  

so

Vcylinder=3Vcone  

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Answer:

19+8*5+8=67

Step-by-step explanation:

when you add 19 with 8 then you times it with 5 then add 8 you get 67

5 0
2 years ago
An electrician has a piece of wire that is 18 feet long. He cuts off 14% of the wire. Then he cuts the remaining pieces of wire
Ronch [10]

Answer:

the 3 pieces are 5.16ft each and the 14% that he cut off is 2.52 ft

Step-by-step explanation:

the 14 % that he cut off is 2.52ft

he has 15.48ft left

15.48/3=5.16

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3 years ago
What is the slope of the line with the equation <br> y = −4/5x+1/2
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Hope This Helped! Good Luck!

7 0
2 years ago
A dog weighs two pounds less than three times the weight of a cat. The dog also weights twenty-two more pounds than the cat. Wri
8090 [49]

Answer:

Weight of dog: 34 pounds,

Weight of cat: 12 pounds.

Step-by-step explanation:

Let d represent weight of dog and c represent weight of cat.

We have been given that a dog weighs two pounds less than three times the weight of a cat.

3 times weight of cat: 3c

We can represent the given information in an equation as:

d=3c-2...(1)

We are also told that the dog also weights twenty-two more pounds than the cat. We can represent the given information in an equation as:

d=c+22...(2)

Equate both equations:

3c-2=c+22

3c-c-2=c-c+22

2c-2=22

2c-2+2=22+2

2c=24

\frac{2c}{2}=\frac{24}{2}

c=12

Therefore, the weight of cat is 12 pounds.

Substitute c=12 in equation (2)

d=c+22

d=12+22

d=34

Therefore, the weight of dog is 34 pounds.

4 0
3 years ago
Jdjfhfjfjfkdjdjdu fhj ch fjfjdkdk
insens350 [35]
The anwser is 40 becuase when you add 24+16=40
6 0
2 years ago
Read 2 more answers
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