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Ymorist [56]
3 years ago
11

What single decimal multiplier would you use to decrease by 2% followed by a 7% decrease?

Mathematics
1 answer:
serg [7]3 years ago
3 0
Here is your answer.

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Evaluate 2 + 4/5 n for n = 1/4
Sophie [7]

Answer:

2\frac{1}{5}

Step-by-step explanation:

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Based only on the information given in the diagram which congruence theorem or postulates would be given as reason why HEL=PME
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I would mark answers:

HL, HA, ASA.

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3 years ago
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Austin keeps a right conical basin for the birds in his garden as represented in the diagram. The basin is 40 centimeters deep,
Lina20 [59]

The shortest distance between the tip of the cone and its rim exits 51.11cm.

<h3>What is the shortest distance between the tip of the cone and its rim?​</h3>

If you draw a line along the middle of the cone, you'd finish up with two right triangles and the line even bisects the angle between the sloping sides. The shortest distance between the tip of the cone and its rim exists in the hypotenuse of a right triangle with one angle calculating 38.5°. So, utilizing trigonometry and allowing x as the measurement of the shortest distance between the tip of the cone and its rim.

Cos 38.5 = 40 / x

Solving the value of x, we get

Multiply both sides by x

$\cos \left(38.5^{\circ}\right) x=\frac{40}{x} x

$\cos \left(38.5^{\circ}\right) x=40

Divide both sides by $\cos \left(38.5^{\circ}\right)$

$\frac{\cos \left(38.5^{\circ}\right) x}{\cos \left(38.5^{\circ}\right)}=\frac{40}{\cos \left(38.5^{\circ}\right)}

simplifying the above equation, we get

$x=\frac{40}{\cos \left(38.5^{\circ}\right)}

x = 51.11cm

The shortest distance between the tip of the cone and its rim exits 51.11cm.

To learn more about right triangles refer to:

brainly.com/question/12111621

#SPJ9

7 0
1 year ago
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If c (x) = StartFraction 5 Over x minus 2 EndFraction and d(x) = x + 3, what is the domain of (cd)(x)?
Volgvan

Answer:

The domain of the function (cd)(x) will be all real values of x except x = 2.

Step-by-step explanation:

The two functions are c(x) = \frac{5}{x - 2} and d(x) = x + 3

So, (cd)(x) = (\frac{5}{x - 2})(x + 3) = \frac{5(x + 3)}{x - 2}

Then, for x = 2 the function (cd)(x) will be undefined as zero in the denominator will make the function (cd)(x) undefined.

Therefore, the domain of the function (cd)(x) will be all real values of x except x = 2. (Answer)

8 0
3 years ago
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HELP?!!!!! Name the space figure you can form from the net.
daser333 [38]

Answer:

a or b but i think a

Step-by-step explanation:

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