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Makovka662 [10]
3 years ago
7

When x2+3x-4 is subtracted from x (x2+3x-2) what is the difference

Mathematics
2 answers:
tankabanditka [31]3 years ago
5 0
I'm assuming this is x^2 + 3x - 4 and x(x^2 + 3x - 2)

1.) First distribute x(x^2 + 3x - 2) to get x^3 + 3x^2 - 2x.

2.) Because you are subtracting all the terms from x^3 + 3x^2 - 2x, it's the same thing as distributing -1 to x^2 + 3x - 4 and then adding it to x^3 + 3x^2 - 2x.

3.) -1(x^2 + 3x - 4) = -x^2 - 3x + 4

4.) Add (x^3 + 3x^2 - 2x) + (-x^2 - 3x + 4)

5.) x^3 + 2x^2 - 5x + 4 is your final answer.

anygoal [31]3 years ago
3 0
Assuming that the problem is  (x^2+3x-4) - x(x^2+3x-2) then this would be simple.. simplifying XD
here is the work for you:
(x^2+3x-4) - x(x^2+3x-2)
(x^2+3x-4) - (x^3+3x^2-2x)
Final Answer: -x^3-2x^2+5x-4

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Answer:

Step-by-step explanation:

7 0
3 years ago
Write an equation and solve the unknown
KATRIN_1 [288]
6 - x = 2x

6 = 2x + x

6 = 3x
———-
3

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I believe take away means subtraction??
4 0
3 years ago
Find the slope of the line that passes through (14, -26) and (15, 14).
tatuchka [14]

Answer:

Slope is 40

Full equation: y=40x-586

Step-by-step explanation:

Slope is y2-y1/x2-x1

14 is x1

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15 is x2

14 is y2

14-(-26)/15-14

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So the slope is 40

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Equation:

y=40x-586

5 0
3 years ago
5 (i + 2) = 8 (i -1)
Vinil7 [7]
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i = 6
5 0
3 years ago
Which of the following sets could be the sides of a right triangle?
MArishka [77]
In a right triangle the sum of the squares of the lengths of two shorter sides is equal to the square of the length of the longest side.

a.
2^2+3^2=(\sqrt{13})^2 \\
4+9=13 \\
13=13 \\ true

b.
2^2+2^2=4^2 \\
4+4=16 \\
8=16 \\
not \ true

c.
1^2+(\sqrt{3})^2=2^2 \\
1+3=4 \\
4=4 \\
true

The answer is A and C.
5 0
3 years ago
Read 2 more answers
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