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olya-2409 [2.1K]
3 years ago
6

Determine the expression

Mathematics
1 answer:
Charra [1.4K]3 years ago
3 0

trinomial and i believe its a degree of 4

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Assume that male and female births are equally likely and that the birth of any child does not affect the probability of the gen
erma4kov [3.2K]
You need to use the binomial probability formula:
p(k) =  \frac{n!}{k!(n-k)!}  p^{k}  (1-p)^{n-k}

where:
n = total number of events = 10
k = number of events we are testing = 6
p = probability of event happening = 0.5

p(6) = \frac{10!}{6!(10-6)!} 0.5^{6} (1-0.5)^{10-6}
= 210×0.015625×0.0625
= 0.205078

Hence, the probability of getting 6 boys out of 10 births is p = 0.205.
6 0
4 years ago
Are the terms 1a and 1b like terms?
Anettt [7]
Well, they are ALIKE, but since a and b are different the terms are different. Hope this helped.
3 0
3 years ago
Since this is no where on here
lakkis [162]

Answer:

B)

Hope that helps! Or is it for our own good? Either way, thanks!

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
After standardizing a NaOH solution, you use it to titrate an HCl solution known to have a concentration of 0.205 M. You perform
Gnoma [55]

Answer:

The right answer is:

(a) 0.205

(b) 0.005425

Step-by-step explanation:

The given data is:

0.213, 0.204, 0.208, 0.200, and 0.198

(a)

The mean will be:

= \frac{Sum \ of \ all \ data}{No. \ of \ data}

= \frac{0.213+ 0.204+ 0.208+ 0.200+0.198}{5}

= \frac{1.023}{5}

= 0.2046

or,

= 0.205

(b)

The standard deviation will be:

\sigma^2=\Sigma\frac{(x_i-\mu)^2}{N}

    =\frac{(0.213-0.2046)^2+...+(0.198-0.2046)^2}{5}

    =\frac{0.0001472}{5}

    =2.994\times 10^{-5}

or,

    =0.005425

7 0
3 years ago
Eighty percent of students surveyed said they feel more focused after exercising. Nine hundred fifty students were surveyed. How
Kisachek [45]
There is 760 more students that feel focused
6 0
3 years ago
Read 2 more answers
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