If sin Ф=1/3>0 and tan Ф<0; then Ф belongs to the second quadrant and cos Ф will be negative (cos Ф<0).
sin²Ф+cos²Ф=1
(1/3)²+cos²Ф=1
1/9+cos²Ф=1
cos²Ф=1-1/9
cos²Ф=8/9
cos Ф=⁺₋√(8/9)=⁺₋2√2 / 3
We have two possible solutions.
cos Ф=2√2 / 3 This solutions is not possible, because in this case cos Ф has to be negative (cos Ф<0)
cos Ф=(-2√2) / 3 this solutions is right.
answer:B. -2 square root 2 /3 (or (-2√2) /3 )
Answer:
For a polynomial of the form ax2+bx+c a x 2 + b x + c , rewrite the middle term as a sum of two terms whose product is a⋅c=2⋅−2=−4 a ⋅ c = 2 ⋅ - 2 = - 4 and whose sum is b=−3 b = - 3 . Factor −3 - 3 out of −3x - 3 x .
Step-by-step explanation:
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Answer:
$69.75
Step-by-step explanation:
Multiply $2.25 by 31 students
Andre : Anything less than -100, for example -150
-150<-100
|-150|=150
Han: Anything between -100 & 100, for example 50
50> 100
|50|= 50
Lin: 100 or -100,
100> -100
|100|=100
or
-100=-100
|-100|=100
