The vertex of this parabola is at (3,-2). When the x-value is 4, the y-value is 3: (4,3) is a point on the parabola. Let's use the standard equation of a parabola in vertex form:
y-k = a(x-h)^2, where (h,k) is the vertex (here (3,-2)) and (x,y): (4,3) is another point on the parabola. Since (3,-2) is the lowest point of the parabola, and (4,3) is thus higher up, we know that the parabola opens up.
Substituting the given info into the equation y-k = a(x-h)^2, we get:
3-[-2] = a(4-3)^2, or 5 = a(1)^2. Thus, a = 5, and the equation of the parabola is
y+2 = 5(x-3)^2 The coefficient of the x^2 term is thus 5.
Answer:
y+2 = -4/5(x-3)
Step-by-step explanation:
The point slope form of a line is
y-y1 = m(x-x1) where m is the slope and (x1,y1) is the point
y - -2 = -4/5(x-3)
y+2 = -4/5(x-3)
You are correct my mom is a teacher and she said you are
Answer:
Option A is correct.
Step-by-step explanation:
Given: 
; 
for n = 2
= 
for n =3
= 
Simlarly , for n =4
= 
and so on...
Common ratio(r) states that for a geometric sequence or geometric series, the common ratio is the ratio of a term to the previous term.
we have; 
Now; by recursive formula for geometric series:
where 
is the first term and r is the common ratio:
Substitute the value of and 
we have;
therefore, the explicit rule for the geometric sequence is;
