300 miles.
1 inch is 200 miles
half an inch is 100 miles
200 plus 100 equals 300 miles
Answer:
Step-by-step explanation:
Given the following coin values ;
A) 1/2 B. 3 cents C. 20 cents D. $2 1/2 E. $5, state it's worth as a percentage of $1
A) $1/2 as a percentage of $1
$1/2 = $0.5
($0.5/ $1) × 100% = 50%
B) 3 cent as a percentage of $1
3 cent = 3/100 = $0.03
($0.03/$1) × 100% = 3%
Answer:
(c) Point A is not on a bisector
Step-by-step explanation:
The figure shows you AR > AT. Since AX is the same for both triangles, angle AXR must be greater than angle AXT. This means AX is not the bisector of angle X.
Since AT is perpendicular to XT, it cannot be the perpendicular bisector of XT. That bisector will intersect XT at its midpoint, not its end.
The marked distances show you that A is different distances from T and R.
The only statement that makes any sense is ...
Point A is not on a bisector.
In this problem, you apply principles in trigonometry. Since it is not mentioned, you will not assume that the triangle is a special triangle such as the right triangle. Hence, you cannot use Pythagorean formulas. The only equations you can use is the Law of Sines and Law of Cosines.
For finding side a, you can answer this easily by the Law of Cosines. The equation is
a2=b2 +c2 -2bccosA
a2 = 11^2 + 8^2 -2(11)(8)(cos54)
a2 = 81.55
a = √81.55
a = 9
Then, we use the Law of Sines to find angles B and C. The formula would be
a/sinA = b/sinB = c/sinC
9/sin54° = 11/sinB
B = 80.4°
9/sin54° = 8/sinC
C = 45.6°
The answer would be: a ≈ 9, C ≈ 45.6, B ≈ 80.4