Answer:
Increasing if f' >0 and decreasing if f'<0
Step-by-step explanation:
Difference quotient got by getting
will be greater than 0 if function is increasing otherwise negative
Here h is a small positive value.
In other words, we find that whenever first derivative of a function f(x) is positive the function is increasing.
Here given that for x1, x2 where x1<x2, we have
if f(x1) <f(x2) then the function is decreasing.
Or if x1<x2 and if f(x1) >f(x2) for all x1, and x2 in I the open interval we say f(x) is decreasing in I.
Answer:
Step-By-Step Explanation:
Answer:b
Step-by-step explanation: $0.50 a year
Answer:
f(x)= -(x^3+10x^2-275x-1500) Standard
f(x)= -(x+20)(x+5)(x-15)
Step-by-step explanation:
The factored form of the equation is:
(x+20)(x+5)(x-15)=f(x) Each of the zeroes are where the graph crosses the x-axis.
The expanded form of the equation is found by using FOIL on the equations above:
-x^3+10x^2-275X-1500
The leading coefficient is negative because the graph rises to the left and falls to the right.
