-3 or -6 Use, or to compare the following numbers.

A video game maker claims that number of glitches in code for their

svet-max [94.6K]

Answer:

The major condition that needs to be satisfied before a t-test is performed that the question satisfies easily is the use of random sampling to obtain sample data.

Step-by-step explanation:

The major conditions necessary to conduct a t-test about a mean include;

- The sample extracted from the population must be extracted using random sampling. That is, the sample must be a random sample of the population.

- The sampling distribution must be normal or approximately normal. This is achievable when the population distribution is normal or approximately normal.

- Each observation in the sample data must have an independent outcome. That is, the outcome/result of each sub-data mustn't depend on one another.

Of the three conditions that need to be satisfied before the conduction of a t-test, the first condition about using a random sampling technique is evidently satisfied.

It is stated in the question that 'A private investigator hired by a competitor takes a random sample of 47 games and tries to determine if there are more than 7 glitches per game'.

Hope this Helps!!!

5 0

4 years ago

The line $y = 3$ intersects the graph of $y = 4x^2 + x - 1$ at the points $A$ and $B$. The distance between $A$ and $B$ can be w

raketka [301]

Answer:

61

Step-by-step explanation:

Let's find the points $A$ and $B$ .

We know that the $y$ -coordinates of both are $3$ .

So let's first solve:

$3=4x^2+x-1$

Subtract 3 on both sides:

$0=4x^2+x-1-3$

Simplify:

$0=4x^2+x-4$

I'm going to use the quadratic formula, $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ , to solve.

We must first compare to the quadratic equation, $ax^2+bx+c=0$ .

$a=4$

$b=1$

$c=-4$

$\frac{-1 \pm \sqrt{1^2-4(4)(-4)}}{2(4)}$

$\frac{-1 \pm \sqrt{1+64}}{8}$

$\frac{-1 \pm \sqrt{65}}{8}$

Since the distance between the points $A$ and $B$ is horizontal. We know this because they share the same $y-coordinate$ .This means we just need to find the positive difference between the $x$ -values we found for the points of $A$ and $B$ .