Let

denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by

, each independently and identically distributed with distribution

.
You want to find

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

Recall that if

, then the sampling distribution

with

being the size of the sample.
Transforming to the standard normal distribution, you have

so that in this case,

and the probability is equivalent to

Answer:
w=-7/3 and w=-9/5
Step-by-step explanation:
Given: 15w^2+62w+63=0
Factor: (3w+7)(5w+9)=0
Zero Product Property: 3w+7=0 and 5w+9=0
Solve each equation: w=-7/3 and w=-9/5
Let me know if you would like me to explain more.
The right answer for the question that is being asked and shown above is that: "D. Three fractions, arranged from left to right, separated by commas. Begin fraction four over seven end fraction. Begin fraction three over five end fraction. Begin fraction five over nine end fraction."