393216 times 4 because you could continue it on until u get to nine
If we draw the contingency table of x (vertical) against y (horiz.), we have a square.
For n=4, we have (legend: < : x<y = : x=y > : x>y
y 1 2 3 4
x
1 = < < <
2 > = < <
3 > > = <
4 > > > =
We see that there are n(n-1)/2 cases of x<y out of n^2.
Therefore,
p(x<y)=n(n-1)/(2n^2)=(n-1)/(2n)
However, if the sample space is continuous, it will be simply p(x<y)=1/2.
Question:
In a neighbourhood pet show, each of the animals entered is equally likely to win. if there are 7 dogs, 6 cats, 3 birds, and 2 gerbils entered, what is the probability that a bird will win the top prize?
Answer:
Probability that a bird will win the top prize is 0.167
Step-by-step explanation:
Given:
The number of dogs = 7
The number of cats = 6
The number of birds = 3
The number of gerbils = 2
To Find:
Probability that a bird will win the top prize = ?
Solution:
Let us first find the total number of pets .
The Total number of pets = 7 + 6 + 3 + 2 = 18
Now the probability of a bird will win the top prize is
=> 
=>
=> 
=>0.167
Answer:
if you need to evaluate it its
Evaluate.
9=−1
however if you need to
Determine if True its False
hoped that help