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Volgvan
2 years ago
15

Identify the slope and y intercept of the function y = - 8x + 1

Mathematics
2 answers:
Maru [420]2 years ago
8 0

Answer:

Slope: -8

Y intercept: (0,1)

Step-by-step explanation:

^^^^

Kazeer [188]2 years ago
6 0

Answer:

\star\mathtt{Ans.\:\#1:\:Slope:-8}

\star\mathtt{Ans.\:\#2:\:y\:intercept:\:1}

Step-by-step explanation:

Hi student, let me help you out.

<u>................................................................................................................</u>

<u></u>

First note that the equation we are working with is in slope intercept form. Do you remember the slope intercept form equation? It's \mathtt{y=mx+b}.

In the slope intercept form equation, "m" denotes "slope" and "b" denotes "y intercept".

Looking back at our equation, let's work out the slope & y intercept.

Let's put these two equations together:

\mathtt{y=mx+b}

\mathtt{y=-8x+1}

See what I mean? The y intercept of this equation is 1 and the slope is -8.

Hope this helped you out! Ask in comments if any queries arise.

Best wishes from "reflect"!

\star\bigstar\underline{\overline{\overline{\underline{\textsf{Reach far. Aim high. Dream big.}}}}}\bigstar\star

\underline{\rule{300}{6}}

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Archy [21]

<u>Answer-</u>

<em>Perimeter of the kite is </em><em>16.2 units</em>

<u>Solution-</u>

As WXYZ is a kite, so two disjoint pairs of consecutive sides are congruent, i.e WX=XY and WZ=ZY

So, perimeter of the kite WXYZ is,

=2(\overline{WX}+\overline{WZ})

And

\overline{WX}=\sqrt{(1-3)^2+(1-4)^2}=\sqrt{(-2)^2+(-3)^2}=\sqrt{4+9}=\sqrt{13}

\overline{WZ}=\sqrt{(1-3)^2+(1+3)^2}=\sqrt{(-2)^2+(4)^2}=\sqrt{4+16}=\sqrt{20}

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P=2(\sqrt{13}+\sqrt{20})=16.15\approx 16.2\ units

4 0
3 years ago
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Answer:

(x- \frac{2}{5})^{2} = x^2 -\frac{4}{5}x + \frac{4}{25}

Step-by-step explanation:

You have two methods to expand this binomial.

Method 1  

If you have the expression:

(x- \frac{2}{5})^{2}

You can write the expression it in the following way:

(x-\frac{2}{5})^{2}=(x-\frac{2}{5})(x-\frac{2}{5})

Then, apply the distributive property:

(x-\frac{2}{5})(x-\frac{2}{5}) = x^2 -\frac{2}{5}x -\frac{2}{5}x+ (\frac{2}{5})\frac{2}{5}

Simplify the expression:

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---------------------------------------------------------------------------------------

Method 2

For any expression of the form:

(a-b)^2

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If

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(x- \frac{2}{5})^{2} = x^2 - 2x\frac{2}{5} + (\frac{2}{5})^2

(x- \frac{2}{5})^{2} = x^2 -\frac{4}{5}x + \frac{4}{25}

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