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2 years ago

Identify the slope and y intercept of the function y = - 8x + 1

Mathematics

2 answers:

Maru [420]2 years ago

8 0

Answer:

Slope: -8

Y intercept: (0,1)

Step-by-step explanation:

^^^^

Kazeer [188]2 years ago

6 0

Answer:

$\star\mathtt{Ans.\:\#1:\:Slope:-8}$

$\star\mathtt{Ans.\:\#2:\:y\:intercept:\:1}$

Step-by-step explanation:

Hi student, let me help you out.

................................................................................................................

First note that the equation we are working with is in slope intercept form. Do you remember the slope intercept form equation? It's $\mathtt{y=mx+b}$ .

In the slope intercept form equation, "m" denotes "slope" and "b" denotes "y intercept".

Looking back at our equation, let's work out the slope & y intercept.

Let's put these two equations together:

$\mathtt{y=mx+b}$

$\mathtt{y=-8x+1}$

See what I mean? The y intercept of this equation is 1 and the slope is -8.

Hope this helped you out! Ask in comments if any queries arise.

Best wishes from "reflect"!

$\star\bigstar\underline{\overline{\overline{\underline{\textsf{Reach far. Aim high. Dream big.}}}}}\bigstar\star$

$\underline{\rule{300}{6}}$

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Find integers a, b, and c such that a) a | (b - c) but a - b and a - c b) a | (2b + 3c) but a - b and a - c

seraphim [82]

Answer:

Part a) (a,b,c)=(10,19,9)

Part b) (a,b,c)=(9,3,1)

Please let be know if I have interpreted your question correctly. Thank you.

Step-by-step explanation:

Part a)

This is the way I interpret part a:

Find integers a,b,c such that a|(b-c) but a does not divide b and a does not divide c.

There are many triples satisfying part a.

One such triple is (a,b,c)=(3,10,7).

3 divides 10-7

But 3 does not divide 10 and 3 does not divide 7.

Another example is (a,b,c)=(2,7,5).

2 divides 7-5

But 2 doesn't divide 7 and 2 doesn't divide 5.

I will give another example.

(a,b,c)=(10,19,9)

10 divides 19-9

But 10 doesn't divide 19 and 10 doesn't divide 9

Part b)

This is the say I interpret part b:

a | (2b + 3c) but a does not divide b and a does not divide c

So lets let b=2 and c=5, then 2b+3c=19.

We just need to choose an a such that it divides 19 but not 2 and 5. That should be easy. 19 itself will do that.

So one (a,b,c) could be (19,2,5).

Let's try for another example.

Let b=3 and c=1.

Then 2b+3c=9.

So we just need to find an a that divides 9 but not 3 and not 1.

9 works.

So another example is (9, 3,1).

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Can someone tell me the answer to this question

Firdavs [7]

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Answer:

Step-by-step explanation:

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