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3 years ago

Need help... Solve this Word Problem

Mathematics

1 answer:

polet [3.4K]3 years ago

8 0

y+z=10

x+z=8

x+y=12

(y+z)-(x+z)=10-8

y-x=2

y+x=12

solve simultaneously

x=5, y=7

then substitute to get z=3

hence xyz=573

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Can u pls help me with this

BabaBlast [244]

Answer:

Problem 1:

x=12, x=3, x=6

Problem 2:

18*3=54

54/18=3

Problem 3:

Part A: 36/4.5=? 4.5*x=36

Part B: 8

Step-by-step explanation:

7 0

2 years ago

Solve the quadratic equation for x. What is one of the roots? (x − 5)2 = 9

Sonja [21]

Answer:

x=8, x=2

Step-by-step explanation:

(x-5)^2=9 Solve by completing the square

Find square root of both sides

|x-5|=3

x=8, x=2

7 0

3 years ago

Read 2 more answers

Jason has $800 more than Paul. Alex has $150 less than Jason. How much more does Alex have than Paul?

jolli1 [7]

Hey there!!

Jason = 800 + Paul

Alex = Jason - 150

How much more does Alex have the Paul?

Let's take the equation of Alex

... Alex = Jason - 150

... Add 150 on both sides

... Alex + 150 = Jason

Now we have the equation for Jason,

... Jason = 800 + Paul , and we got Alex + 150 = Jason

... Now let's plug in the values

... Alex + 150 = 800 + Paul

Subtract 150 on both sides...

Alex = 800 - 150 + Paul

... Alex = 650 + Paul

Now we got the answer for our question :

The answer - Alex has $650 than Paul.

Hope my answer helps!!

4 0

3 years ago

Below are two parallel lines with a third line intersecting them.

Allushta [10]

180-48= 132 ( I think)

8 0

2 years ago

I NEED HELP PLEASE, THANKS! :)

Elena L [17]

Answer:

First option is the right choice.

Step-by-step explanation:

$\frac{1}{\cos \left(x\right)+1}+\frac{1}{\cos \left(x\right)-1}\\\\\frac{\cos \left(x\right)-1}{\left(\cos \left(x\right)+1\right)\left(\cos \left(x\right)-1\right)}+\frac{\cos \left(x\right)+1}{\left(\cos \left(x\right)+1\right)\left(\cos \left(x\right)-1\right)}\\\\=\frac{\cos \left(x\right)-1+\cos \left(x\right)+1}{\left(\cos \left(x\right)+1\right)\left(\cos \left(x\right)-1\right)}\\\\=\frac{2cos\left(x\right)}{cos^2\left(x\right)-1}\\\\=\frac{2cos\left(x\right)}{sin^2\left(x\right)}$

$=2\cdot \frac{cos\left(x\right)}{sin\left(x\right)}\cdot \frac{1}{sin\left(x\right)}\\\\=-2cot(x)csc(x)$

Best Regards!

7 0

3 years ago