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3 years ago

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Mathematics

2 answers:

arsen [322]3 years ago

6 0

Answer:

Step-by-step explanation:

$G = \sqrt{ \frac{m - 5}{2} }$

To make m the subject square both sides of the equation

That's

$\frac{m - 5}{2} = {G}^{2}$

Cross multiply

m - 5 = 2G²

Move 5 to the right side of the equation to make m stand alone

We have the final answer as

Hope this helps you

DochEvi [55]3 years ago

6 0

Answer:

A semi-circle sits on top of a rectangle to form the figure below. Find its area and perimeter. Use 3.14 for .

The rectangle is 4 inches long and 3 inches wide. The semi-circle sits on top of the rectangle on a side that is 4 inches long.

Step-by-step explanation:

You might be interested in

A line is perpendicular to y = -x + 1

frozen [14]

Answer: The equation of the perpendicular line intersects the point (-5,1) is y=x+6[/tex]

Step-by-step explanation:

step1:-

The standard form of slope - intercept form y=m x+c

Here m is called slope of the given line

C is called the y- intercept of the given line

Given equation of the straight line y=-x+1

comparing the slope - intercept form y=m x+c

here m= -1 and c=1

step2:-

The equation of the perpendicular line is

$y-{[y_{1}$ } =\frac{-1}{m} (x-x_{1} )[/tex]

substitute m = -1 and c =1 values in equation

$y-1 =\frac{-1}{-1} (x-(-5 )$

$y-1 ={1} (x-(-5 )$

$y=1+x+5\\y=x+6$

step3:- The equation of the perpendicular line intersects the point (-5,1) is

y=x+6[/tex]

<u>conclusion</u><u>:</u>-

The equation of the perpendicular line is

y=x+6[/tex]

4 0

3 years ago

What is the product of 2/3 and 1/5

garik1379 [7]

2/15
2 * 1 is 2
3 * 5 is 15

4 0

2 years ago

Amelia enjoys running and often runs at a steady pace. At this pace, Amelia can run 50 yards in 12 seconds. What is Amelia's uni

valentinak56 [21]

Answer:

4.16

Step-by-step explanation:

50/12

7 0

2 years ago

Please help me how to do no 5

snow_tiger [21]

Answer:

-864

Step-by-step explanation:

The determinant of a matrix product is the product of the determinants. The determinant of a transpose is the same as the determinant of the original. Hence ...

$|AB^5C^T|=(4)(-2)^5(\frac{1}{4})=-32$

The multiplication of an n×n matrix by a scalar 'a' multiplies its determinant by a^n, so the desired determinant is ...

$|3AB^5C^T|=3^3(-32) = \boxed{-864}$

3 0

3 years ago

2 tens and 76 ones equals

garri49 [273]

It equals 96. hope that helped

5 0

3 years ago

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