Given:
Two vectors (u) and (w) and the angle between them θ
the sketch of the vectors will be as shown in the following figure:
As shown, the resultant vector is the blue line segment
The vector R has a magnitude = 60.22
And the angle between u and R = 5.56°
The parts of a circle are the r<em>adius, diameter, circumference, arc, chord, secant, tangent, sector and segment.</em>
Radius:
The distance from the center to any point on the circle.
Diameter:
The distance across the circle through the center point.
Circumference:
The distance around a circle.
Arc:
arcs in the same circle that have exactly one point in common. measure of arc divided by 360 multiplied by the circumference. the length of an arc. semicircle. an arc that is half of a circle; always measures 180 degrees.
Chord:
a line segment that connects two points of a circle.
Secant:
A secant is a line that intersects a circle in two points.
Tangent:
A tangent is a line that intersects the circle in exactly one point.
Sector:
region bounded by an arc of a circle and the two radii to the arc's endpoints. - A sector is like a "pizza slice" of the circle. It consists of a region bounded by two radii and an arc lying between the radii.
Segment:
A segment or length of a segment with one endpoint at the center of the circle.
Answer:
Step-by-step explanation:
Given that:-
The speed of the orion= 20,000 miles per hour
Time = 1 hour ( From source )
Thus,
Distance = Speed * Time = 20,000*1 miles = 20,000 miles
Thus, in 1 hour, the orion can travel 20,000 miles
Also,
93,000,000 miles = 1 astronomical unit
1 mile = 1/93,000,000 astronomical unit
20,000 miles = (1/93,000,000)*20,000 astronomical unit
<u>The orion can travel AU in one hour.</u>
Answer:
The required equation is .
Step-by-step explanation:
Consider the provided information.
The Initial value of poster = $ 18
After 1 year amount of increase = $ 20.70
With the rate of 15% = 0.15
Let future value is y and the number of years be x.
Now verify this by substituting x=1 in above equation.
Which is true.
Hence, the required equation is .