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Diano4ka-milaya [45]

3 years ago

10

A=20 find the volume round to the nearest 10th

1 answer:

lianna [129]3 years ago

8 0

Are you sure there weren't any other numbers in the problem? You can't solve for the volume with out at least two numbers for length, width, or height. Or are you solving for a cube?

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Alina [70]

Answer:

the answer would be b

Step-by-step explanation:

hoped that helped:P

8 0

2 years ago

what is the probability that a card picked at random from a 52-card deck of playing cards is a club or a jack?

ASHA 777 [7]

$|\Omega|=52\\ |A|=\underbrace{13}_{\text{clubs}}+\underbrace{4}_{\text{jacks}}-\underbrace{1}_{\text{jack of clubs}}=16\\\\ P(A)=\dfrac{16}{52}=\dfrac{4}{13}\approx31\%$

7 0

3 years ago

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PLEASE HELP!!!!!!!! WILL MARK AS BRAINLIEST!!!!!

Ratling [72]

A.) 2, 7

and heres other words so i can send it

7 0

2 years ago

In rectangle abcd, points p and q lie on side AB and DC respectively. Angle PMQ is a right angle, M is the midpoint of side BC a

nirvana33 [79]

Answer:

PM:MQ = 8:3.

Step-by-step explanation:

$\rm \angle B\hat{M}P + 90^{\circ} + \angle C\hat{M}Q = 180^{\circ}$ ;

$\implies \rm \angle B\hat{M}P + \angle C\hat{M}Q = 90^{\circ}$ ;

$\implies \rm 90^{\circ} - \angle B\hat{M}P = \angle C\hat{M}Q$ .

Also,

$\rm \angle B\hat{P}M = 90^{\circ} - \angle B\hat{M}P$ in right triangle PBM.

Thus $\rm \angle{P\hat{B}M} = \angle C\hat{M}Q$ .

Additionally $\rm \angle \hat{B} = 90^{\circ} = \angle \hat{C}$ .

Therefore $\rm \triangle PBM \sim \triangle MCQ$ .

$\rm \displaystyle BC = 2\;MC$ for M is the midpoint of segment BC.

$\rm \displaystyle PB = \frac{4}{3}BC = \frac{8}{3}MC$ .

$\rm \triangle PBM \sim \triangle MCQ$ implies that

$\displaystyle \rm PM:MQ = PB:MC = 1:\frac{8}{3} = 8:3$ .

8 0

3 years ago

Please someone help me if you can't that is okay but please try I am extremely desperate

Snowcat [4.5K]

A, you combine like terms

7 0

2 years ago

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