1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Setler [38]
3 years ago
14

Hosea borrowed $20,000 to buy a new speed boat. The interest rate on his loan is 5%. If he plans to pay the loan back in three y

ears, how much interest will he pay? What will be the total cost that he will owe including interest?
Mathematics
1 answer:
Anit [1.1K]3 years ago
7 0

Answer:

a. Interest amount is $3,000.

b. Total cost is $23,000.

Step-by-step explanation:

a. How much interest will he pay

This can be calculated as follows:

Interest amount = Principal loan Amount * Interest rate * Number of years ........ (1)

Where;

Principal loan Amount = $20,000

Interest rate = 5%

Number of years = 3

Substituting the values into equation (1), we have:

Interest amount = $20,000 * 5% * 3 = $3,000

b. What will be the total cost that he will owe including interest?

Total cost = Principal loan Amount + Interest amount = $20,000 + $3,000 = $23,000

You might be interested in
Line BC reflects about a line such that N is the reflection of B and O is the reflection of C. Point N is shown on the coordinat
erik [133]
    If the line BC reflects about a line and point N( 3, 5 ) is the reflection of point B ( 3 , 7 ) then the reflection of C ( 5, 7 ) is O ( 5 , 5 ).
Answer: C ) ( 5, 5 ) 
3 0
3 years ago
Read 2 more answers
How can i prove this property to be true for all values of n, using mathematical induction.
chubhunter [2.5K]

Proof -

So, in the first part we'll verify by taking n = 1.

\implies \: 1  =  {1}^{2}  =  \frac{1(1 + 1)(2 + 1)}{6}

\implies{ \frac{1(2)(3)}{6} }

\implies{ 1}

Therefore, it is true for the first part.

In the second part we will assume that,

\: {  {1}^{2} +  {2}^{2}  +  {3}^{2}  + ..... +  {k}^{2}  =  \frac{k(k + 1)(2k + 1)}{6}  }

and we will prove that,

\sf{ \: { {1}^{2} +  {2}^{2}  +  {3}^{2}  + ..... +  {k}^{2}  + (k + 1)^{2} =  \frac{(k + 1)(k + 1 + 1) \{2(k + 1) + 1\}}{6}}}

\: {{1}^{2} +  {2}^{2}  +  {3}^{2}  + ..... +  {k}^{2}  + (k + 1)^{2}  =  \frac{(k + 1)(k + 2) (2k + 3)}{6}}

{1}^{2} +  {2}^{2}  +  {3}^{2}  + ..... +  {k}^{2}  + (k + 1)^{2} = \frac{k (k + 1) (2k + 1) }{6} +  \frac{(k + 1) ^{2} }{6}

{1}^{2} +  {2}^{2}  +  {3}^{2}  + ..... +  {k}^{2}  + (k + 1)^{2} = \frac{k(k+1)(2k+1)+6(k+1)^ 2 }{6}

{1}^{2} +  {2}^{2}  +  {3}^{2}  + ..... +  {k}^{2}  + (k + 1)^{2} = \frac{(k+1)\{k(2k+1)+6(k+1)\} }{6}

{1}^{2} +  {2}^{2}  +  {3}^{2}  + ..... +  {k}^{2}  + (k + 1)^{2} = \frac{(k+1)(2k^2 +k+6k+6) }{6}

{1}^{2} +  {2}^{2}  +  {3}^{2}  + ..... +  {k}^{2}  + (k + 1)^{2} = \frac{(k+1)(2k^2+7k+6) }{6}

{1}^{2} +  {2}^{2}  +  {3}^{2}  + ..... +  {k}^{2}  + (k + 1)^{2} = \frac{(k+1)(k+2)(2k+3) }{6}

<u>Henceforth, by </u><u>using </u><u>the </u><u>principle </u><u>of </u><u> mathematical induction 1²+2² +3²+....+n² = n(n+1)(2n+1)/ 6 for all positive integers n</u>.

_______________________________

<em>Please scroll left - right to view the full solution.</em>

8 0
2 years ago
Find the greatest solution for x+y when x^2+y^2 = 7, x^3+y^3=10
damaskus [11]

Answer:

4

Step-by-step explanation:

set

f(x,y)=x+y\\

constrain:

g(x,y)=x^2+y^2 = 7\\h(x,y)=x^3+y^3=10

Partial derivatives:

f_{x}=1\\f_{y} =1 \\g_{x}=2x \\g_{y}=2y\\h_{x}=3x^2 \\h_{y}=3y^2

Lagrange multiplier:

grad(f)=a*grad(g)+b*grad(h)\\

\left[\begin{array}{ccc}1\\1\end{array}\right]=a\left[\begin{array}{ccc}2x\\2y\end{array}\right]+b\left[\begin{array}{ccc}3x^2\\3y^2\end{array}\right]

4 equations:

1=2ax+3bx^2\\1=2ay+3by^2\\x^2+y^2=7\\x^3+y^3=10

By solving:

a=4/9\\b=-2/27\\x+y=4

Second mathod:

Solve for x^2+y^2 = 7, x^3+y^3=10 first:

x=\frac{1}{2} -\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} +\frac{\sqrt{13}}{2} \\x=\frac{1}{2} +\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} -\frac{\sqrt{13}}{2} \\x+y=-5\ or\ 1 \or\ 4

The maximum is 4

6 0
3 years ago
Simplify the following problem.<br> (-8+61) +(6+61)
Travka [436]

Answer: -8+61 = 53 and 6+61 = 67

3 0
3 years ago
A square has an area of 64 square units. A cube has a volume of 64 cubic units. What is the difference in the side length of the
Rina8888 [55]
The formula in solving the area of a square is Area = a² where "a" is for the length of the side. The area formula in solving a cube is Area = 6a² where "a" is for the length of its side.
Area of square = a²
64 = a²
a = 8 units

Area of cube = 6a²
64= 6a²
a = 3.27 units 

The difference of side of the square and side of the cube is shown below:
Difference = 8 - 3.27
Difference = 4.73 units.

The answer is 4.73 units.
4 0
3 years ago
Other questions:
  • Sum or difference in simplest form 5/12 -1/4 =
    5·2 answers
  • Solve for x. <br><br> −1/5x≥−2
    9·1 answer
  • Asmaa is shopping for an infant car seat. She has a coupon for 20% off any purchase over $35
    6·2 answers
  • Solve the following using scientific notation and standard notation:
    14·2 answers
  • The equation k equals C + 273 relates temperatures in kelvins K and degrees Celsius C what is C in terms of K
    15·1 answer
  • 1. What net force is required to accelerate a car at a rate of 2 m/s2
    8·1 answer
  • How many possible lunches can be consisting of one entree, one drink and one snack? ​
    7·2 answers
  • Solve for x in the triangle
    13·1 answer
  • What is the decimal equivalent of 8/3?<br> A. 2.6<br> B. 0.375<br> C. 8.3<br> D. 26
    7·2 answers
  • Solve for a.<br> -2 &gt; a/-1 -4<br> please explain step by step to get a brainliest
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!