Answer:
See explanation
Explanation:
Hello there!
In this case, since the the concentrations are not given, and not even the Ksp, we can solve this problem by setting up the chemical equation, the equilibrium constant expression and the ICE table only:

Next, the equilibrium expression according to the produced aqueous species as the solid silver chloride is not involved in there:
![Ksp=[Ag^+][Cl^-]](https://tex.z-dn.net/?f=Ksp%3D%5BAg%5E%2B%5D%5BCl%5E-%5D)
And therefore, the ICE table, in which x stands for the molar solubility of the silver chloride:

I - 0 0
C - +x +x
E - x x
Which leads to the following modified equilibrium expression:

Unfortunately, values were not given, and they cannot be arbitrarily assigned or assumed.
Regards!
Answer:
2Li + F₂ → 2LiF
Explanation:
The reaction expression is given as:
Li + F₂ → LiF
We are to balance the expression. In that case, the number of atoms on both sides of the expression must be the same.
Let use a mathematical approach to solve this problem;
Assign variables a,b and c as the coefficients that will balance the expression:
aLi + bF₂ → cLiF
Conserving Li: a = c
F: 2b = c
let a = 1, c = 1 and b =
Multiply through by 2;
a = 2, b = 1 and c = 2
2Li + F₂ → 2LiF
Answer:
The answer to your question is below
Explanation:
An atom with four electrons in its valence shell is capable of forming:
single bonds and atom with the described characteristics, can form 4 single bonds or a combination of single bonds and double or triple bonds. Ex alkanes
double bonds this atom can form one double bond and two single bonds or two double bonds. Ex alkenes
triple bonds this atom can form one triple bond and one single bond, Ex alkynes.
Answer: b. the volume of water vapour increases
Explanation:
when there's an increase in concentration, the equilibrium favours the forward reaction, more product is produced, froward reaction is faster
Answer:
36.23 %
Explanation:
Let's <em>assume we have 1 mol of FeCl₂ · 4H₂O</em>. In that case we would have:
- 1 mol of FeCl₂, weighing 126.75 g (that's the molar mass of FeCl₂), and
- 4 moles of H₂O, weighing (4 * 18 g/mol) 72 g.
Now we can <u>calculate the percent by mass of water</u>:
- % mass = mass of water / total mass * 100%
- % mass =
* 100% = 36.23 %