Answer:
C18H38(s) + O2(g) → CO₂(g) + H₂O(g).
Explanation:
C₁₈H₃₈ is called Octadecane and it is an Alkane as the molecular formula follows the general formula of Alkanes which is CnH2n+2 .
C₁₈H₃₈ reacts with Oxygen and forms Carbon Dioxide (CO₂) and Water (H₂O).
We can say that on oxidation Octadecane gives Carbon Dioxide (CO₂) and Water (H₂O) because on passing Oxygen over Octadecane the above products are formed.
C18H38(s) + O2(g) → CO₂(g) + H₂O(g).
The molecular weight of methane (CH4) is 16.04 g / mol.
Therefore:
22.8 grams x (mol) / 16.04 g =
(Grams unit cancel out)
1.42 mol
The correct answer is Sulfur (S).
Sulfur has 6 valence electrons because it is located in Group 16 (or the sixth group over if you don’t count the transition metals). This means that one atom of sulfur has 6 electrons in its outermost shell out of 8 total “spots”, which you can count by counting the group numbers (excluding the transition metals) from Group 1 (with one valence electron) to Group 18 (the noble gases with full valence or outer shells).
By this same logic, Carbon (C) has 4 valence electrons and Cesium (Cs) has 1 valence electron, so neither of these is the correct answer.
Hope this helps!
Answer:
A
Explanation:
Increasing the the temperature would favour the endothermic reaction which is the forward direction however increasing the pressure would make the reaction try to counteract this change by favouring the reaction that would create more products so the equilibrium will shift left instead of right.
Hope this helps.
