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3 years ago

Find (1/3 + 5/6 - 1/6) / (4/5)

Mathematics

2 answers:

Marta_Voda [28]3 years ago

5 0

Answer:

$\frac{5}{4}$

Step-by-step explanation:

$(\frac{1}{3} + \frac{5}{6} - \frac{1}{6}) \div \frac{4}{5}\\\\( \frac{2 + 5 - 1}{6}) \div \frac{4}{5} \\\\(\frac{6}{6}) \div \frac{4}{5}\\\\\frac{1}{\frac{4}{5}}\\\\\frac{5}{4}$

Nataliya [291]3 years ago

3 0

Answer:

5/4

Step-by-step explanation:

A simpler approach:

(1/3+5/6-1/6):(4/5)=

(1/3+4/6):(4/5)=

(1/3+2/3):(4/5)=

1:(4/5)=

5/4

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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3 years ago

If sin theta= - 5/7, which of the following are possible?

Sphinxa [80]

Answer:

$\large\boxed{\sec\theta=\dfrac{7}{\sqrt{24}},\ and\ \tan\theta=-\dfrac{5}{\sqrt{24}}}\\\boxed{\cos\theta=\dfrac{\sqrt{24}}{7},\ and\ \tan\theta=\dfrac{5}{\sqrt{24}}}$

Step-by-step explanation:

$\text{Use:}\\\\\sin^2\theta+\cos^2\theta=1\to\cos\theta=\pm\sqrt{1-\sin^2\theta}\\\\\tan\theta=\dfrac{\sin\theta}{\cos\theta}\\\\\sec\theta=\dfrac{1}{\cos\theta}\\\\==========================\\\\\sin\theta=-\dfrac{5}{7}\\\\\cos\theta=\pm\sqrt{1-\left(-\frac{5}{7}\right)^2}=\pm\sqrt{1-\frac{25}{49}}=\pm\sqrt{\frac{24}{49}}=\pm\dfrac{\sqrt{24}}{\sqrt{49}}=\pm\dfrac{\sqrt{24}}{7}\\\\\sec\theta=\pm\dfrac{1}{\frac{\sqrt{24}}{7}}=\pm\dfrac{7}{\sqrt{24}}$

$\tan\theta=\pm\dfrac{-\frac{5}{7}}{\frac{\sqrt{24}}{7}}=\mp\dfrac{5}{7\!\!\!\!\diagup_1}\cdot\dfrac{7\!\!\!\!\diagup^1}{\sqrt{24}}=\mp\dfrac{5}{\sqrt{24}}$

$\sin\theta=-\dfrac{5}{7}$

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3 years ago

Find (1/3 + 5/6 - 1/6) / (4/5)​

Find (1/3 + 5/6 - 1/6) / (4/5)