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Nikolay [14]
3 years ago
13

What is the value of y in the equation 5x + 2y = 20, when x = 0.3?

Mathematics
2 answers:
White raven [17]3 years ago
7 0
First substitute x for 0.3 and multiply by 5, and you get 1.5 Now we want to isolate the 2y so we subtract 1.5 on both sides. So we have a new equation of 2y=18.5 Now to isolate the y we divide 2 by both sides and you get y=9.25
ANTONII [103]3 years ago
4 0

Answer:

y=9.25

Step-by-step explanation:

5x+2y=20

5(.3)+2y=20

1.5+2y=20

2y=20-1.5

2y=18.5

y=18.5/2

y=9.25

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3 0
3 years ago
Help me pleaseeeeeeeeeeeeeee
dangina [55]

Answer:

W=1000C/tc

Step-by-step explanation:

First multiply both side 1000: 1000C=Wtc

Divide both side by tc: 1000C/tc=W (t, c ≠0)

7 0
3 years ago
Find the arc length of a central angle of 7pi/3 in a circle whose radius is 3 inches.
skelet666 [1.2K]

\bf \textit{arc's length}\\\\ s=r\theta ~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad radians\\ \hrulefill\\ r=3\\ \theta =\frac{7\pi }{3} \end{cases}\implies s=3\cdot \cfrac{7\pi }{3}\implies s=7\pi

4 0
3 years ago
Read 2 more answers
Match the following terms by evaluating the expression for x=-6
Scorpion4ik [409]
The sum of 2 opposites =0
X+6 would now equal 0
So your answer is 0
5 0
3 years ago
A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set w
VashaNatasha [74]

Complete Question

A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set was split into 5 segments (each 6.4 seconds long), what is the resulting:

a)F minimum

b) F maximum

c) Frequency resolution

Answer:

a) Fmax=100Hz

b) Fmin=0Hz

c) F_r=0.0313

Step-by-step explanation:

From the question we are told that:

Time t=32sec

FrequencyF=200Hz

Segments \mu=5

Generally the equation for Frequency Range is mathematically given by

Fmax=\frac{F}{2}

Fmax=100Hz

Therefore

a) Fmax=100Hz

b) Fmin=0Hz

c)

Generally the equation for Frequency Resolution is mathematically given by

F_r=\frac{F}{N}

Where

N=The Total dat points

N=Sampling Frequency *Time

N=200*32

N=6400

Therefore

F_r=\frac{200}{6400}

F_r=0.0313

6 0
3 years ago
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