When you heat an atom, some of its electrons are "excited* to higher energy levels. When an electron drops from one level to a lower energy level, it emits a quantum of energy. ... The different mix of energy differences for each atom produces different colours. Each metal gives a characteristic flame emission spectrum.
Intensity has no affect on whether or not the photoelectric effect occurs. The determining property is frequency and since frequency and wavelength are inversely proportional, wavelength matters as well. If a frequency of light can't cause the photoelectric effect to happen, no matter what the intensity is, the light can't make it happen.
I hope this helps. Let me know in the comments if anything is unclear.
Answer:
Polar covalent bond
Explanation:
When the electronegativity difference between two elements A and X is 0.8, the bond AX formed will most likely be a polar covalent bond.
A polar covalent bond is one whose electronegativity difference is between 0.5 and 2.1.
In such a bond type, we have heteronuclear species with one of the species having a higher electronegativity value.
- When electronegativity difference is less than 0.5, a non-polar covalent bond forms.
- If the value is greater than 2.1, an ionic bond will form.
Answer:
9.9 moles of Ag₂S contain 9.9 moles of sulfur.
Explanation:
Given data:
Number of moles of Ag₂S = 9.9 mol
Number of moles of Sulfur = ?
Solution:
One mole of Ag₂S having 1 mole of sulfur.
In 9.9 moles:
9.9 moles × 1 = 9.9 moles
So 9.9 moles of Ag₂S contain 9.9 moles of sulfur.
