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neonofarm [45]
3 years ago
7

Hi! Which of the following decreases kinetic energy of solvent molecules? ( I need this handed in quickly!)

Chemistry
1 answer:
Black_prince [1.1K]3 years ago
4 0

Answer:

c

Explanation:

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How many grams of sulfur are required in the preparation of 35.7 moles of sulfur dioxide Sg + O2 SO2​
lidiya [134]
  • S+O_2-->SO_2

Its balanced already

So

  • 1 mol SO_2 require 1 mole sulphur
  • 35.7moles require 35.7mol sulphur

Mass of S

  • 35.7(32)
  • 1142.4g
6 0
2 years ago
Forces between similar molecules are said to be
podryga [215]

Answer:

Forces between similar molecules are said to be <em>cohesive</em> while those between different types of molecules are said to be <em>adhesive</em>.

Water 'beads' due to its strong <em>cohesive</em> forces. The meniscus of water in a glass tube is <em>concave</em> because the <em>adhesive</em> forces are strong.

Explanation:

The water in a tube has stronger adhesive forces between the water and glass molecules, so the cohesive forces between water molecules are weaker. That makes the water 'ascend' through the tube, giving a concave form of the meniscus. Another example is mercury, which is the opposite. In this case, the cohesive forces are stronger than the adhesive ones, thus the meniscus is convex.

4 0
3 years ago
Write a letter to your friend describing your feelings after you left the school
fredd [130]
Dear friend,
How are you doing? I finally switched to my new school and it's been so hard adjusting. But I know I have a new chance at making new friends and memories. Also, I can learn new things, like interacting with new people and how to keep my anxiety low. I really miss us hanging out and how much we'd laugh and get in trouble at class. But i really hope to see you soon & that it hasn't gone terribly wrong for you since i left.
your friend,
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8 0
3 years ago
Which of the following situations contains an example of a chemical reaction?
bogdanovich [222]

A bicycle rusting after it is left in the rain is an example of a chemical reaction because it involves oxidation (Option d).  

<h3>What is a chemical reaction?</h3>

A chemical reaction can be defined as a phenomenon in which one or more substances called reactants react to form one or more different compounds, which are known as products.

A chemical reaction may include an enzyme that works to increase the seed of the reaction in normal conditions by lowering the activation energy of the reaction.

Therefore, we can conclude that a chemical reaction such as oxidation in a bicycle is a process where reactants combine or break down to form the products of such reaction.

Complete question:

Which of the following situations contains an example of a chemical reaction?

a. Ice forming after water is placed in a freezer

b. Watercolor paint drying on paper

c. a sugar cube dissolving in a glass of water

d. a bicycle rusting after it is left in the rain

Learn more about chemical reactions here:

brainly.com/question/11231920

#SPJ1

6 0
1 year ago
Consider the following reaction between mercury(II) chloride and oxalate ion.
Alina [70]

<u>Answer:</u> The rate law of the reaction is \text{Rate}=k[HgCl_2][C_2O_4^{2-}]^2

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

2 HgCl_2(aq.)+C_2O_4^{2-}(aq.)\rightarrow 2Cl^-(aq.)+2CO_2(g)+Hg_2Cl_2(s)

Rate law expression for the reaction:

\text{Rate}=k[HgCl_2]^a[C_2O_4^{2-}]^b

where,

a = order with respect to HgCl_2

b = order with respect to C_2O_4^{2-}

Expression for rate law for first observation:

3.2\times 10^{-5}=k(0.164)^a(0.15)^b  ....(1)

Expression for rate law for second observation:

2.9\times 10^{-4}=k(0.164)^a(0.45)^b  ....(2)

Expression for rate law for third observation:

1.4\times 10^{-4}=k(0.082)^a(0.45)^b  ....(3)

Expression for rate law for fourth observation:

4.8\times 10^{-5}=k(0.246)^a(0.15)^b  ....(4)  

Dividing 2 from 1, we get:

\frac{2.9\times 10^{-4}}{3.2\times 10^{-5}}=\frac{(0.164)^a(0.45)^b}{(0.164)^a(0.15)^b}\\\\9=3^b\\b=2

Dividing 2 from 3, we get:

\frac{2.9\times 10^{-4}}{1.4\times 10^{-4}}=\frac{(0.164)^a(0.45)^b}{(0.082)^a(0.45)^b}\\\\2=2^a\\a=1

Thus, the rate law becomes:

\text{Rate}=k[HgCl_2]^1[C_2O_4^{2-}]^2

3 0
3 years ago
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