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natta225 [31]
3 years ago
9

Given h(x)=-2x+1,find h(-6)

Mathematics
1 answer:
Vesna [10]3 years ago
7 0

Answer:

h = -11

Step-by-step explanation:

x=-6 so...

2*(-6)+1= -11

h= -11

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Find the smallest relation containing the relation {(1, 2), (1, 4), (3, 3), (4, 1)} that is:
professor190 [17]

Answer:

Remember, if B is a set, R is a relation in B and a is related with b (aRb or (a,b))

1. R is reflexive if for each element a∈B, aRa.

2. R is symmetric if satisfies that if aRb then bRa.

3. R is transitive if satisfies that if aRb and bRc then aRc.

Then, our set B is \{1,2,3,4\}.

a) We need to find a relation R reflexive and transitive that contain the relation R1=\{(1, 2), (1, 4), (3, 3), (4, 1)\}

Then, we need:

1. That 1R1, 2R2, 3R3, 4R4 to the relation be reflexive and,

2. Observe that

  • 1R4 and 4R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 4R1 and 1R2, then 4 must be related with 2.

Therefore \{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(4,1),(4,2)\} is the smallest relation containing the relation R1.

b) We need a new relation symmetric and transitive, then

  • since 1R2, then 2 must be related with 1.
  • since 1R4, 4 must be related with 1.

and the analysis for be transitive is the same that we did in a).

Observe that

  • 1R2 and 2R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 2R1 and 1R4, then 2 must be related with 4.
  • 4R1 and 1R2, then 4 must be related with 2.
  • 2R4 and 4R2, then 2 must be related with itself

Therefore, the smallest relation containing R1 that is symmetric and transitive is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

c) We need a new relation reflexive, symmetric and transitive containing R1.

For be reflexive

  • 1 must be related with 1,
  • 2 must be related with 2,
  • 3 must be related with 3,
  • 4 must be related with 4

For be symmetric

  • since 1R2, 2 must be related with 1,
  • since 1R4, 4 must be related with 1.

For be transitive

  • Since 4R1 and 1R2, 4 must be related with 2,
  • since 2R1 and 1R4, 2 must be related with 4.

Then, the smallest relation reflexive, symmetric and transitive containing R1 is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

5 0
3 years ago
Full question and options​
LekaFEV [45]

Answer:

D

Step-by-step explanation:

A triangle is always determined by the names of its angles. If, for any reason, you wanted to label it by its side names(which I don't even think you can do but assuming you wanted to), you dont even have the names for all three sides here. So, it can only be d. A, X, and T are the three angle names for this triangle, so this is triangle ATX or AXT.

8 0
2 years ago
Read 2 more answers
20 ounce sodas cost 4 for $5. How much does each soda cost?
dolphi86 [110]
I think 1.99?
I have no idea but I think it’s that
3 0
3 years ago
Reese deposited $7500 for two years into a money market account. At the end of two years, she earned $1200 interest. What rate o
icang [17]

Answer:

She deposited $7500. So it is the principal.

At the end of  years, she had total of $8700.

So the total amount is $8700 and the time period is 2 years.

Interest = Total amount - principal = $8700 - $7500 = $1200

We need the rate of interest.

we know that Interest = PTR/100

⇒1200 = 7500*2*R/100

⇒R = 1200*100/7500*2

⇒R = 120000/15000 = 8%

Rate of interest is 8%

Step-by-step explanation:

6 0
3 years ago
In six years, clem kadiddlehopper will be five time as old he was 26 years ago. how old is he now?
levacccp [35]

Answer:

he is currently 34

Step-by-step explanation:

x + 6 = 5(x-26)

x + 6 = 5x - 130

 +130        +130

x + 136 = 5x

-x             -x

136 = 4x

/4       /4

x = 34

You can check your work as well:

34 + 6 = 40

34 - 26 = 8

8 x 5 = 40

3 0
3 years ago
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