Question

What's is an equation of the line that passes through the point(-3,-1) and is perpendicular to the line x-2y=6

Answer 1

Answer:

$y+1=-2(x+3)$

Step-by-step explanation:

Slope is negative reciprocal when two lines are perpendicular

m1=1/2 therefore m2=-2

The equation of the line in point-slope form is given as

$y-y_1=m_2(x-x_1)$

Here m=-2 and (x1, y1)=(-3, -1)

Therefore,

$y+1=-2(x+3)$