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3 years ago

What are the adjacent and vertical pairs in this picture

Mathematics

1 answer:

luda_lava [24]3 years ago

5 0

Answer:

Step-by-step explanation:

Two line segments AD and CE intersects at a point B.

Two angles which represent the pair of adjacent angles are,

∠ABC and ∠DBC

Pair of vertical angles (Opposite angles between two intersecting lines) is,

∠ABE and ∠CBD

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*PLEASE HELP*

Evgesh-ka [11]

3^2+10^2=c^2

9+100=c^2

109=c^2

Square root both sides and you get:

10.44

(I’m pretty sure I’m right but make sure you double check good lucky

7 0

3 years ago

3-2+x+ 436 123/157 =

sweet [91]

3 - 2 + x + 436 123/157 =

1 + x + 436 123/157 =

437 123/157 + x =

68732/157 + x

6 0

2 years ago

Read 2 more answers

Find an equation of the circle that satisfies the given conditions. (Give your answer in terms of x and y.) Center at the origin

Elanso [62]

Answer:

The equation of circle is $x^2+y^2=65$ .

Step-by-step explanation:

It is given that the circle passes through the point (8,1) and center at the origin.

The distance between any point and the circle and center is called radius. it means radius of the given circle is the distance between (0,0) and (8,1).

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula the radius of circle is

$r=\sqrt{\left(8-0\right)^2+\left(1-0\right)^2}=\sqrt{65}$

The standard form of a circle is

$(x-h)^2+(y-k)^2=r^2$ .... (1)

where, (h,k) is center and r is radius.

The center of the circle is (0,0). So h=0 and k=0.

Substitute h=0, k=0 and $r=\sqrt{65}$ in equation (1).

$(x-0)^2+(y-0)^2=(\sqrt{65})^2$

$x^2+y^2=65$

Therefore the equation of circle is $x^2+y^2=65$ .

5 0

3 years ago

The circumference of a circle is 20π m. What is the area, in square meters? Express your answer in terms of \piπ.

never [62]

Answer:

A≈31.83

Step-by-step explanation:

pls can i have brainliest

7 0

2 years ago

Under his cell phone plan, Ian pays a flat cost of $59.50 per month and $5 per gigabyte. He wants to keep his bill under $80 per

inessss [21]

You would start by saying his budget is $80 so you start with 80= he pays an initial fee of $59.50 every month plus $5 per gigabyte so you would set it up like
80=59.50+5x
X being how many gigabytes he uses then you solve 80-59.50 is 20.5 divided by 5 gives you 4.1 but you round down cause you don’t want to pass the limit so therefor the most gigabytes he can use is 4

3 0

3 years ago