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3 years ago

PLZ HELP 60 POINTS!!!!!

Mathematics

2 answers:

ratelena [41]3 years ago

7 0

Answer: Vector travelling 4 units to the left and 1 unit up, facing northwest.

Step-by-step explanation:

The original shape is ABC, while the translated shape is A'B'C'.

The translation is 4 units to the left and 1 unit up.

The correct vector will display as a vector travelling 4 units across and 1 unit down, facing northwest.

The first attached image travels 4 units across and 1 unit down, and faces the correct direction (northwest).

The second attached image travels 4 units across and 1 unit down, but it faces the wrong direction (southeast).

The third image travels 1 unit across and 2 units down. This is incorrect.

The fourth image travels 1 unit across and 2 units down. This is incorrect.

The correct answer is the first attached image (linked in comments)

Tom [10]3 years ago

4 0

Answer:

translation is 1 unit up, 4 units left.

vector is on image 2

Step-by-step explanation:

triangle ABC translated to is A'B'C'.

The translation is 1 unit up, 4 units left.

<u>the correct vector is on image 2</u>

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Describe how you would find the missing numbers in the equation below. What is the missing numerator and denominator?

Ugo [173]

Answer:

3 and 5 is the correct answer in this question

Step-by-step explanation:

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2 years ago

A storage shed is to be built in the shape of a (closed) box with a square base. It is to have a volume of 150 cubic feet. The c

Alenkinab [10]

Answer:

$C(s) = 6s^2 + \dfrac{1500}{s}\\\text{where s is the side of base.}$

Step-by-step explanation:

We are given the following in the question:

A storage shed is to be built in the shape of a (closed) box with a square base.

Volume = 150 cubic feet

Let s be the edge of square base and h be the height.

Volume of cuboid =

$l\times b\times h$

where l is the length, b is the base and h is the height.

Volume of box =

$s^2h = 150\\\\h = \dfrac{150}{s^2}$

Area of base =

$\text{side}\times \text{side} = s^2$

Cost of concrete for the base = $4

Cost of base($) = $4s^2$

Area of roof =

$\text{side}\times \text{side} = s^2$

Cost of material for the roof = $2

Cost of roof ($) = $2s^2$

Area of 4 walls =

$4\times (sh)\\=4sh$

Cost of material for the side = $2.50

Cost of material of side($) =

$2.50\times 4s(\dfrac{150}{s^2})\\\\=\dfrac{1500}{s}$

Total cost

= Cost of base + Cost of 4 sides + Cost of roof

$C(s) = 4s^2 + \dfrac{1500}{s} + 2s^2\\\\C(s) = 6s^2 + \dfrac{1500}{s}$

is the required cost function.

5 0

3 years ago

The radius of circle C is 6 units and the measure of central angle ACB is I radians. What is the approximate area of the entire

VARVARA [1.3K]

Answer:

Step-by-step explanation:

see attachment

3 0

3 years ago

Read 2 more answers

Please help picture included!!

Triss [41]

I think the answer is C

8 0

4 years ago

I need help with this graph.

tatuchka [14]

Two parallel lines never intersect, therefore they will never have a solution.

One line could be x=6 and the other could be x=2

Hope this helps :)

3 0

3 years ago