Not unless the digits in each period are also in the same order. That is, the digit in each PLACE must be the same.
There are eight, if I'm understanding the question correctly. 8 is in the ten thousands place, at least
-
Kskkzkzkzkskskamamiixushvsjsjajahhzuzyahsuxushvzxhyxxhb
Answer:
- 13
Step-by-step explanation:
To evaluate h(j(2)) substitute x = 2 into j(x) then substitute the value obtained into h(x)
j(2) = - 2 × 2 = - 4, then
h(- 4) = (3 × - 4) - 1 = - 12 - 1 = - 13
Hence h(j(2)) = - 13
What are the choices? You should have inserted a picture.
