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postnew [5]
3 years ago
13

Help . Please need done in 15 minutes

Mathematics
1 answer:
tigry1 [53]3 years ago
4 0

29.4% that he will at least score 5 times. :D

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Does this table represent a function? Why or why not?
nordsb [41]

no the x and y axis both have repeating numbers

8 0
2 years ago
Which statements describe the functions? Check all
Novosadov [1.4K]

Answer: A,b,e

A:Each successive output is the previous output divided by 3.

B:As the domain values increase, the range values decrease.

E:The range of the function is all real numbers greater than 0.

These are the answers on e2020. Hope this helps

4 0
3 years ago
Write an inequality that represents the graph.
Anika [276]

Answer:

y - 2x - 1 = 0

Step-by-step explanation:

the slope is :

\tan( \alpha )  = 4  \div 2 = 2

at a pt on graph , when

x = 1 \\ y = 3 \\

therefore, coordinates are (1,3)

The equation is :

(y - 3) = slope \times (x - 1) \\ (y - 3) = 2 \times (x - 1) \\  y - 3 = 2x - 2 \\ y - 2x - 1 = 0

5 0
2 years ago
You drink a beverage with 120 mg of caffeine. Each hour, the caffeine in your system decreases by about 12%. How long until you
uysha [10]

Answer:

  19.44 hours, about 19 hours 26 minutes

Step-by-step explanation:

The exponential equation that describes your caffeine level can be written as ...

  c(t) = 120·(1 -0.12)^t . . . . where t is in hours and c(t) is in mg

We want to find t for c(t) = 10, so ...

  10 = 120(0.88^t)

  10/120 = 0.88^t . . . . . . . divide by 120

  log(1/12) = t·log(0.88) . . . take logarithms

  t = log(1/12)/log(0.88) ≈ 19.4386

It will take about 19.44 hours, or 19 hours 26 minutes, for the caffeine level in your system to decrease to 10 mg.

3 0
3 years ago
If α, β are the zeroes of the polynomials f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1) =
Pavlova-9 [17]

Answer:

f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)

Step-by-step f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)explanation:

f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(xf(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1) + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(xf(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1) + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)

4 0
3 years ago
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