V initial = l*w*h;
V final = (2/3)l*(2/3)w*(2/3)h = (l*w*h)*(8/9) = V initial * (8/9) ;
Answer:
first you need to place a point for the vertex of the new angle. then take the compass and place it on the vertex of angle DBC and draw a circle around it. without adjusting the compass, move it to the vertex that you had placed and draw the same size circle around it. Draw a base line for the new angle . Then go to the point of intersection on angle DBC where the circle intersects both of the sides. place your compass on both intersection points. move that to the point of intersection on the new angle and draw a circle. then connect the points.
Answer:
Yes, Tom must be admitted to this university.
Step-by-step explanation:
We are given that the scores on national test are normally distributed with a mean of 500 and a standard deviation of 100.
Also, we are provided with the condition that Tom wants to be admitted to this university and he knows that he must score better than at least 70% of the students who took the test.
Let, X = score in national test, so X ~ N(
)
The standard normal z distribution is given by;
Z =
~ N(0,1)
Now, z score of probability that tom scores 585 is;
Z =
= 0.85
Now, proportion of students scoring below 85% marks is given by;
P(Z < 0.85) = 0.80234
This shows that Tom scored 80.23% of the students who took test while he just have to score more than 70%.
So, it means that Tom must be admitted to this university.
Answer:
20 20/27
Step-by-step explanation:
(2 2/3)(3 1/3)(2 1/3) = (8/3)(10/3)(7/3) = 560/27 = 20 20/27
_____
<em>Additional comment</em>
The first two numbers can be written as a difference and a sum:
= (3 -1/3)(3 +1/3)(2 1/3)
= (3·3 -1/3·3 +3·1/3 -1/3·1/3)(2 1/3)
= (9 -1/9)(2 +1/3) = 9·2 +9·1/3 -1/9·2 -1/9·1/3 = 18 +3 -6/27 -1/27
= 20 20/27
Answer:
<em>Results below</em>
Step-by-step explanation:
<u>Equation of the line</u>
A straight line can be written in the form:
y = ax + b
Where a and b are constants and x is the independent variable.
The essential condition for an equation to be linear is that the x must be powered to the exponent 1, which is usually not written.
From the equations presented in the table:
is linear because the exponent of the x is 1
y = 5(x+2) = 5x + 10 is linear with a=5 and b=10.
y = x is linear with a=1 and b=0
is not linear because the exponent of x is 2
is not linear because the exponent of x is 2
The table below summarizes the results