Answer:
B . Yes
Step-by-step explanation:
Recall: a tangent of a circle is perpendicular to the radius of a circle, forming a right angle at the point of tangency.
Therefore, if segment ST is tangent to circle P, it means that m<T = 90°, and ∆PST is a right triangle.
To know if ∆PST is a right triangle, the side lengths should satisfy the Pythagorean triple rule, which is:
c² = a² + b², where,
c = longest side (hypotenuse) = 37
a = 12
b = 35
Plug in the value
37² = 12² + 35²
1,369 = 1,369 (true)
Therefore we can conclude that ∆PST is a right triangle, this implies that m<T = 90°.
Thus, segment ST is a tangent to circle P.
It's the third graph, the one where the absolute function is opening downwards
In order to form triangle PQT and quadrilateral TQRS, point T must lie on line PS which is 16 cm. long.
If the ratio of PT to TS is 5:3 and the total length of PS is 16, then PT must be 10 and TS must be 6 (10 + 6 =16) and 10:6 is the same ratio as 5:3. Another way to think about it is 5/3 = 10/6.
Now you have all the lengths that you need to find the areas of the quadrilateral and the triangle.
Make sure you draw a diagram of it!!
Answer:
A number times five is greater than fifteen. A number less negative seven is less than or equal to five. The difference between a number and seven is less than zero. The sum of a number and seven is greater than or equal to fifteen.
Answer:
lim(x---->0) = -5
Step-by-step explanation:
first: sin(x-π/2)= -cosx
so the equation will be :
lim(x---->0) = [-6cos(ax)-1}/cosx
solve :
lim(x---->0) = [-(6cos(a(0))-1}/cos(0)
cos0=1
lim(x---->0)=(-(6(1)-1)/1
lim(x---->0)=-6+1/1
lim(x---->0)=-5
