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victus00 [196]
3 years ago
15

Two of these numbers are the same value , which ones are they? 40%, .44 ,1/4 , 0.4 , 4/10

Mathematics
1 answer:
Wewaii [24]3 years ago
6 0

Answer:

I'm pretty sure it is 0.4

Step-by-step explanation:

I really hope this helps

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Please help. will give brainliest ​
vichka [17]

Answer:

  • B. The probability that the student received a grade better than C is 0.45

Step-by-step explanation:

<u>Total number of students:</u>

  • 15 + 30 + 35 + 16 + 4 = 100
<h3>Statements</h3>

A.

  • p(<D) = 4/100 = 0.04
  • 0.04 ≠ 0.2
  • Incorrect

B.

  • p(>C) = (30 + 15)/100 = 45/100 = 0.45
  • 0.45 = 0.45
  • Correct

C.

  • p(not A or B) = (100 - 15 - 30)/100 = 55/100 = 0.55
  • 0.55 ≠ 0.45
  • Incorrect

D.

  • p(B or C) = (30 + 35)/100 = 65/100 = 0.65
  • 0.65 ≠ 0.35
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6 0
3 years ago
A 20 foot ladder is leaning against a tree. The bottom of the ladder is 12 feet away from the bottom of the tree. Approximately
Nutka1998 [239]
9.2 is the answer and in your case C.
8 0
3 years ago
Plz help! I will make you the brainliest! Thanks!
Andrews [41]
So to start you will need to divide by -5 then -5 divided by -5 cancelle
4 0
3 years ago
Read 2 more answers
How do you do series with an n
SOVA2 [1]
The problem can be solved step by step, if we know certain basic rules of summation.  Following rules assume summation limits are identical.
\sum{a+b}=\sum{a}+\sum{b}
\sum{kx}=k\sum{x}
\sum_{r=1}^n{1}=n
\sum_{r=1}^n{r}=n(n+1)/2

Armed with the above rules, we can split up the summation into simple terms:
\sum_{r=1}^n{40r-21n+8}=n
=40\sum_{r=1}^n{r}-21n\sum_{r=1}^n{1}+8\sum_{r=1}^n{1}
=40\frac{n(n+1)}{2}-21n^2+8n
=20n(n+1)-21n^2+8n
=28n-n^2

=> (a) f(x)=28n-n^2
=> f'(x)=28-2n 
=> at f'(x)=0 => x=14
Since f''(x)=-2 <0  therefore f(14) is a maximum
(b) f(x) is a maximum when n=14

(c) the maximum value of f(x) is f(14)=196
4 0
3 years ago
This is not math but pls help here are some
devlian [24]

Answer:

There is nothing here do you have a question I would be happy to help!!!:)

Step-by-step explanation:

7 0
2 years ago
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