Answer:
- B. The probability that the student received a grade better than C is 0.45
Step-by-step explanation:
<u>Total number of students:</u>
- 15 + 30 + 35 + 16 + 4 = 100
<h3>Statements</h3>
A.
- p(<D) = 4/100 = 0.04
- 0.04 ≠ 0.2
- Incorrect
B.
- p(>C) = (30 + 15)/100 = 45/100 = 0.45
- 0.45 = 0.45
- Correct
C.
- p(not A or B) = (100 - 15 - 30)/100 = 55/100 = 0.55
- 0.55 ≠ 0.45
- Incorrect
D.
- p(B or C) = (30 + 35)/100 = 65/100 = 0.65
- 0.65 ≠ 0.35
- Incorrect
So to start you will need to divide by -5 then -5 divided by -5 cancelle
The problem can be solved step by step, if we know certain basic rules of summation. Following rules assume summation limits are identical.




Armed with the above rules, we can split up the summation into simple terms:





=> (a)
f(x)=28n-n^2=> f'(x)=28-2n
=> at f'(x)=0 => x=14
Since f''(x)=-2 <0 therefore f(14) is a maximum
(b)
f(x) is a maximum when n=14
(c)
the maximum value of f(x) is f(14)=196
Answer:
There is nothing here do you have a question I would be happy to help!!!:)
Step-by-step explanation: