Is the following relation a function? A. Yes B. No

Mathematics

1 answer:

SVETLANKA909090 [29]1 year ago

3 0

Answer:

B. No

Step-by-step explanation:

In order for the relation to be a function, each X value must source exactly one arrow. The value -1 maps to two different values (2, -1), so the relation is NOT A FUNCTION.

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So, the definite integral $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

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<h3>Definite integrals </h3>

Definite integrals are integral values that are obtained by integrating a function between two values.

So, $Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx$

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