Answer:
It is not normally distributed as it has it main concentration in only one side.
Step-by-step explanation:
So, we are given that the class width is equal to 0.2. Thus we will have that the first class is 0.00 - 0.20, second class is 0.20 - 0.40 and so on(that is 0.2 difference).
So, let us begin the groupings into their different classes, shall we?
Data given:
0.31 0.31 0 0 0 0.19 0.19 0 0.150.15 0 0.01 0.01 0.19 0.19 0.53 0.53 0 0.
(1). 0.00 - 0.20: there are 15 values that falls into this category. That is 0 0 0 0.19 0.19 0 0.15 0.15 0 0.01 0.01 0.19 0.19 0 0.
(2). 0.20 - 0.40: there are 2 values that falls into this category. That is 0.31 0.31
(3). 0.4 - 0.6 : there are 2 values that falls into this category.
(4). 0.6 - 0.8: there 0 values that falls into this category. That is 0.53 0.53.
Class interval frequency.
0.00 - 0.20. 15.
0.20 - 0.40. 2.
0.4 - 0.6. 2.
Answer:
Juan and Luke each ate 9 grapes
Step-by-step explanation:
24 - 6 = 18
18 ÷ 2 = 9
Are you thinking of hundreds? If so, then it would be 307700.
Answer:
A
Step-by-step explanation:
Here, we want to get the number that will be in the units place
Six consecutive numbers from 33 are;
33 , 34 , 35 , 36 , 37 , 38 ,
Product of 5 and any of the even numbers will yield 0
That means the number on the unit place is 0
Answer:
<u><em>21 yard line</em></u>
Step-by-step explanation:
Ok we start out on the 20 yard line, we need to add the yards together.
<em>We add the 6 to the 20:</em>
20+6=26
<em>Then we subtract the 8 yards from our new 26:</em>
26-8=18
<em>Then we add the 18 by 3:</em>
18+3=21
Therefore,
<em>The Answer is 21 Yard Line.</em>
Hope I could help, If you need some more assistance ask me!