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geniusboy [140]
3 years ago
7

What is 15+69-78+95 Explain

Mathematics
2 answers:
gavmur [86]3 years ago
4 0

Answer:

101

Step-by-step explanation:


Natasha_Volkova [10]3 years ago
3 0

Solution, 15+69-78+95=101

Steps:

15+69-78+95

Follow\:the\:PEMDAS\:order\:of\:operations,\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:\:

15+69=84,\\84-78+95

84-78=6,\\6+95

6+95=101,\\101

\mathrm{The\:Correct\:Answer\:is\:101}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

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How many different 4 letter arrangements can be formed from the letters in the word cards
RUDIKE [14]
Slot method
1st slot, 5 options
2nd slot, 4 options (1 gone to the first slot)
3rd slot, 3 options (1 gone again)
4th slot,2 options (1 less)

multiply
5*4*3*2=120

answer is 120 arrangements
5 0
3 years ago
12/31/2021 and 3 million shares at 12/31/2020 (81 million) (59 million) total shareholders’ equity $ 774 million $ 603 million h
kkurt [141]

The number of Levi's common shares that were outstanding on 12/31/2020 is 16,000,000 shares.

<h3>What is an Outstanding common shares?</h3>

This refers to the number of shares of common stock that a company has issued to investors and company executives.

Total common shares

= $95million  / $5 par shares

= 19 million shares

Outstanding common shares = 19 million shares - 3 million shares

Outstanding common shares = 16,000,000 shares

Therefore, the number of Levi's common shares that were outstanding on 12/31/2020 is 16,000,000 shares.

Full information

The following partial information is taken from the comparative balance sheet of Levi Corporation:

Shareholders’ equity 12/31/2021 12/31/2020

Common stock, $5 par; 29 million shares authorized; 24 million shares issued and 19 million shares outstanding at 12/31/2021; and ____million shares issued and ____shares outstanding at 12/31/2020.

$120million $95million

Additional paid-in capital on common stock 529million 401million

Retained earnings 206million 166million

Treasury common stock, at cost, 5 million shares at 12/31/2021 and 3 million shares at 12/31/2020 (81million) (59million)

Total shareholders’ equity $774million $603million

Read more about common shares

brainly.com/question/10718788

#SPJ1

6 0
1 year ago
P l e a s e h e l p p p p !!!
Mandarinka [93]

Answer:

This would be the last option I think, sorry if it's wrong.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The Office of Student Services at a large western state university maintains information on the study habits of its full-time st
Vera_Pavlovna [14]

Answer:

0.8254 = 82.54% probability that the mean of this sample is between 19.25 hours and 21.0 hours

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 20 hours, standard deviation of 6:

This means that \mu = 20, \sigma = 6

Sample of 150:

This means that n = 150, s = \frac{6}{\sqrt{150}}

What is the probability that the mean of this sample is between 19.25 hours and 21.0 hours?

This is the p-value of Z when X = 21 subtracted by the p-value of Z when X = 19.5. So

X = 21

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{21 - 20}{\frac{6}{\sqrt{150}}}

Z = 2.04

Z = 2.04 has a p-value of 0.9793

X = 19.5

Z = \frac{X - \mu}{s}

Z = \frac{19.5 - 20}{\frac{6}{\sqrt{150}}}

Z = -1.02

Z = -1.02 has a p-value of 0.1539

0.9793 - 0.1539 = 0.8254

0.8254 = 82.54% probability that the mean of this sample is between 19.25 hours and 21.0 hours

3 0
3 years ago
PLEASE HELP ME!!
Dmitry_Shevchenko [17]
I think it’s A sorry if it’s wrong!
6 0
2 years ago
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