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2 years ago

Select the correct answer.

Chemistry

1 answer:

givi [52]2 years ago

6 0

Answer:

{1s^2 2s^2 2p^6} 3s^2 3p^4

{Ne}3s^2 3p^4

Explanation:

i didnt understand the rest of that but this is the e- configuration on top and the bottom is noble gas configuration

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9. During an experiment the students prepared three mixtures A)Starch in water B) Sodium chloride solution C) Tincture of Iodine

il63 [147K]

Answer:

See explanation

Explanation:

Tyndall effect refers to the scattering of light in a solution. Tyndall effect occurs when the size of particles in the solution exceeds 1 nm in diameter. Such solutions are actually called false solutions.

In tincture of iodine, the size of particles in solution is less than 1 nm in diameter hence the solution does not exhibit Tyndall effect. Hence, tincture of iodine is a true solution.

Therefore, if the size of particles in solution exceeded 1nm in diameter, Tyndall effect is observed.

7 0

2 years ago

Which elements are out of order in terms of atomic mass. co,Ni or Li,be or I,xe

valkas [14]

Answer:

The pair co,Ni is out of order in terms of atomic mass

Explanation:

For co,Ni

Atomic mass of Co = 58.9331 u

Atomic mass of Ni = 58.6934

For Li,be

Atomic mass of Li = 6.941 u

Atomic mass of be = 9.012182 u

For I,xe

Atomic mass of I = 126.90447 u

Atomic mass of Xe = 131.293 u

Hence, the pair co,Ni is out of order in terms of atomic mass

7 0

2 years ago

Plsplsplsplsplsplsplsplsplspls help

MA_775_DIABLO [31]

Answer:

this is difficult but simple to answer

Explanation:

all atoms move in 1 direction no more than 2

6 0

2 years ago

How many particles would be found in a 1.224 g sample of K2O

lbvjy [14]

Answer:

9.96*10^21

Explanation:

Molar mass of K2O=29*2+16

= 74g per mol

number of moles in the sample= 1.224/ 74

=0.1654

Number of particles in 1 mole=6.0221409*10^23

Number of particles= 0.01654*6.0221409*10^23

=9.96*10^21

4 0

3 years ago

Read 2 more answers

When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 27.6 g of carbon were burned in the presence of

In-s [12.5K]

Answer:

The answer to your question is: 101.2 g of CO2

Explanation:

C = 27.6 g

O₂ = 86.5 g remained 12.9 g

O₂ that reacted = 86.5 - 12.9 = 73.6 g

C + O₂ ⇒ CO₂ The equation is balanced

27.6 73.6 ?

MW 12 32 44

Rule of three

12 g of C------------------ 44 g CO2

27.6 g C ------------------ x

x = 27.6(44)/12 = 101.2 g of CO2

32 g of O2 --------------- 44 g of CO2

73.6 g of O2 ------------ x

x = 73.6(44)/32 = 101.2 g of CO2

6 0

3 years ago