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IRINA_888 [86]
3 years ago
15

Minerals are very useful to us. Which of the following is a false statement? Question options: Pyrite is an ore of gold and is u

sed in jewelry making. Talc is used in paper making, plastics, and paint. Quartz is used to make glass. Cobalt is not used in medicine.
Chemistry
1 answer:
Andrew [12]3 years ago
8 0

Answer:

Option C= Cobalt is not used in medicine

This statement is incorrect.

Explanation:

Pyrite is an ore of gold and is used in jewelry making (correct statement)

Pyrite:

1. pyrite is yellow brass mineral.

2. its chemical composition is  FeS2.

3. it is also called ore of gold

4. it is used in jewelry.

Talc:

Talc is used in paper making, plastics, and paint (correct statement)

1. it is phyllosilicate mineral in the form of sheets.

2. its chemical formula is Mg3Si4O10 (OH)2.

3. it is very important constituent of roofing material.

4. it is used in many industries like paper making, paints, electrical cables, food etc.

Quartz:

Quartz is used to make glass (correct statement)

1. its chemical formula is SiO2.

2. its large amount is used in manufacturing of ceramic and glass.

3. The second most abundant mineral found in the earth crust is also quartz.

Cobalt:

Cobalt is not used in medicine (incorrect statement)

1. Cobalt is widely used in medical field.

2. it is used in the detection of metastasis and tumor.

3. it is used in the replacement of knee and hip as a prosthetic alloys.

Minerals are very important in our daily life. They are widely used in construction material for example in the construction of buildings and roads and also in medical field.

Examples:

1. Copper is used in the electronic and electrical field.

2. Zinc is used in rust resistant metals, skin care creams. rubber paints etc.

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One difference between mixtures and pure substances is that A) mixtures can be physically separated. B) mixtures are made of one
Alborosie
The answer your looking for is a)
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5 0
3 years ago
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Convert 3841 cL to L. SHOW WORK PLS
barxatty [35]

Answer:

1 cl = 1 * 10-5 m³

1 L = 1 * 10-3 m³

1 L = 0.001 m³

1 m³ = (1/0.001) L

1 m³ = 1000 L

1 cl = 1 * 10-5 * 1000 L

1 cl = 0.01 L

4 0
3 years ago
So I saw this question: If 28.0 grams of Pb(NO3)2 react with 18.0 grams of NaI, what mass of PbI2 can be produced? Pb(NO3)2 + Na
Nataly_w [17]

mass of PbI₂ = 27.6606 g

<h3>Further explanation</h3>

Given

Pb(NO₃)₂ + NaI → PbI₂ + NaNO₃

28.0 grams of Pb(NO₃)₂ react with 18.0 grams of NaI

Required

mass of PbI₂

Solution

Balanced equation

Pb(NO₃)₂ + 2NaI → PbI₂ + 2NaNO₃

The principle of a balanced reaction is the number of atoms in the reactants = the number of atoms in the product

mol Pb(NO₃)₂ :

= 28 : 331,2 g/mol

= 0.0845

mol NaI :

= 18 : 149,89 g/mol

= 0.12

Limiting reactant : mol : coefficient

Pb(NO₃)₂ : 0.0845 : 1 = 0.0845

NaI : 0.12 : 2 = 0.06

NaI limiting reactant (smaller ratio)

mol PbI₂ based on NaI

= 1/2 x 0.12 = 0.06

Mass PbI₂ :

= 0.06 x 461,01 g/mol

= 27.6606 g

4 0
3 years ago
A 2.04 g lead weight, initially at 10.8 oC, is submerged in 7.74 g of water at 52.2 oC in an insulated container. clead = 0.128
QveST [7]

Answer:

Explanation:

Hello, in this case, the lead is catching heat and the water losing it, that's why the heat relation ship is (D is for Δ):

DH_{lead}=-DH_{water}

Now, by stating the heat capacity definition:

m_{Pb}C_{Pb}*(T_{eq}-T_{lead}=-m_{H_2O}C_{H_2O}*(T_{eq}-T_{H_2O})\\

Solving for the equilibrium temperature:

T_{eq}=\frac{m_{Pb}C_{Pb}T_{Pb}+m_{H_2O}C_{H_2O}T_{H_2O}}{m_{Pb}C_{Pb}+m_{H_2O}C_{H_2O}} \\\\T_{eq}=\frac{2.04g*0.128J/(g^oC)*10.8^oC+7.74g*4.18J/(g^oC)*52.2^oC}{2.04g*0.128J/(g^oC)+7.74g*4.18J/(g^oC)} \\\\T_{eq}=51.87^oC

Which is very close to the water's temperature since the lead's both mass and head capacity are lower than those for water.

Best regards.

5 0
3 years ago
What is the percent s character in an sp^2 hybridized orbital? 25% 33% 50% 67% 75%
Brums [2.3K]

Answer:

The correct option is: B. 33%

Explanation:

Orbital hybridisation refers to the mixing of atomic orbitals of the atoms in order to form new hybrid orbitals. The concept of orbital hybridization is used to explain the structure of a molecule.

The sp² hybrid orbitals are formed by the hybridization of one 2s orbital and two 2p orbitals. <u>The three sp² hybrid orbitals formed have 33% s character and 67% p character.</u>

8 0
3 years ago
Read 2 more answers
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