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2 years ago

2 C4H10+13 O2 = 8 CO2+10 H2O

Chemistry

1 answer:

Shkiper50 [21]2 years ago

8 0

Answer:

This chemical reaction is a combustion.

n = 1.8mol

Explanation:

The ratio of oxygen to water is 13 to 10

The ratio of oxygen to water is also 43 grams to x

Cross multiply: 13x = 430 grams

Isolate x: x = 33.0769g

Remember that n = mass/Molar mass

The molar mass of water is 18.01528 g/mol

n = 33.0769/18.01528

n = 1.836048

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If you mix calcium hydrogen and carbon how many compounds will you have?

Licemer1 [7]

Answer:

Calcium monohydride is a molecule composed of calcium and hydrogen with formula CaH. It can be found in stars as a gas formed when calcium atoms are present with hydrogen atoms.Calcium carbonate is a chemical compound with the formula CaCO3 formed by three main elements: carbon, oxygen and calcium.

Explanation:

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2 years ago

Barium and lead both produce yellow precipitate with the chromate ion as part of their confirmation tests. if you had a sample t

UkoKoshka [18]

Barium is an element that is primarily used in fireworks because of its distinct green colour while on the other hand, lead is used in electrical industries due to its unique properties. The ions of these elements can simply be identified when its insoluble salts get precipitated by any process.

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3 years ago

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What color are the stars on the diagram with the lowest surface temperatures?

Luba_88 [7]

Answer:

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2 years ago

A 237g sample of molybdnum metal is heated to 100.1 0C and then dropped into an insulated cup containing 244 g of water at 10.0

miv72 [106K]

Answer:

The specific heat of molybdenum is 0.254 joules per gram-Celsius.

Explanation:

We consider the system formed by the molybdenum metal and water as our system, a control mass inside an insulated cup, that is, a container that avoids any energy and mass interactions between system and surroundings.

From statement we notice that metal is cooled down whereas water is heated. According to the First Law of Thermodynamics, we know that:

$Q_{metal} - Q_{water} = 0$

$Q_{metal} = Q_{water}$

Where:

$Q_{water}$ - Heat received by water, measured in joules.

$Q_{metal}$ - Heat released by metal, measured in joules.

Now we expand this identity by definition of sensible heat:

$m_{metal}\cdot c_{metal}\cdot (T_{m,o}-T) = m_{water}\cdot c_{water}\cdot (T-T_{w,o})$

The specific heat of the metal is cleared within equation above:

$c_{metal} = \frac{m_{water}\cdot c_{water}\cdot (T-T_{w,o})}{m_{metal}\cdot (T_{m,o}-T)}$

If we know that $m_{water} = 0.237\,kg$ , $m_{metal} = 0.244\,kg$ , $c_{water} = 4186\,\frac{J}{kg\cdot ^{\circ}C}$ , $T_{w,o} = 10\,^{\circ}C$ , $T_{m,o} = 100.10\,^{\circ}C$ and $T = 15.30\,^{\circ}C$ , the specific heat of molybdenum is:

$c_{metal} = \frac{(0.237\,kg)\cdot \left(4186\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (15.30\,^{\circ}C-10\,^{\circ}C)}{(0.244\,kg)\cdot (100.10\,^{\circ}C-15.30\,^{\circ}C)}$

$c_{metal} = 254.119\,\frac{J}{kg\cdot ^{\circ}C}$

The specific heat of molybdenum is 0.254 joules per gram-Celsius.

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3 years ago

HELP WILL GIVE BRANLIEST

Elodia [21]

Answer:

Boron (B) Atomic Mass: 10.811

Explanation:

The number of protons and electrons are the same, always. You can find the atomic mass by looking at the periodic table for that atom: 10.811

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3 years ago