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4vir4ik [10]
2 years ago
13

2 C4H10+13 O2 = 8 CO2+10 H2O

Chemistry
1 answer:
Shkiper50 [21]2 years ago
8 0

Answer:

This chemical reaction is a combustion.

n = 1.8mol

Explanation:

The ratio of oxygen to water is 13 to 10

The ratio of oxygen to water is also 43 grams to x

Cross multiply: 13x = 430 grams

Isolate x: x = 33.0769g

Remember that n = mass/Molar mass

The molar mass of water is 18.01528 g/mol

n = 33.0769/18.01528

n = 1.836048

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lisov135 [29]

Answer:

True

Explanation:

The first artificial use of a PGR was to stimulate the production of flowers on pineapple plants. They are now used widely in agriculture. Plant hormones are also used in turf management to reduce the need to mow, to suppress seedheads, and to suppress other types of grass.

3 0
3 years ago
In order to change the mass of a compound to number of miles, what is needed?
Svet_ta [14]
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3 years ago
Why phenolphthalein is used in experiment?
Dominik [7]
In an acid-base titration, the neutralization reaction between the acid and base can be measured with either a color indicator or a pH meter. In this experiment, aphenolphthalein<span> color indicator will be </span>used<span>.
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4 0
3 years ago
Given the following: I) N20(g) 1/2 02(g) 2 NO(g) II) N2(g) 02(g) 2 NO(g) Ke= 4.1 x 10-31 Ke= 1.7 x 10-13 Find the value of the e
tresset_1 [31]

Answer:

Answer B) 4.2x10^17

Explanation:

To produce the reaction 3 using reaction 1 and 2 we need to invert the order of the first reaction the second in the same order, as it's shown:

2NO-------->N_2O+1/2O_2 : (reaction 1' :K'_1 =1/K_1=2.4x10^ 3^0)

N_2+O_2-------->2NO: (reaction 2 :K_2 =1.7x10^-^1^3)

____________________________

N_2+1/2O_2-------->N_2O: (reaction 3)

Due to the inversion of the first equation, the equilibrium constant of the new reaction is K1'=1/K1.=2.4x10^30

Finally, the new equilibrium constant K3 is the product of the previous constants:  

K3=K1'*K2=4.2x10^17

6 0
3 years ago
a mixture is made up of 3.35g of SiO2, 0.38g of cellulose and 8.76g of calcium carbonate. What is the percent of cellulose in th
Alchen [17]

Solution:

mass of the cellulose in the mixture is 0.38g

total mass of the mixture is:

3.35+0.38+8.76

=12.4g

thus the  percentage of the cellulose in the mixture is:

mass of the cellulose/total mass of the mixture*100%

0.38/12.4*100%

=3%

6 0
3 years ago
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