Question

A carpenter added a diagonal brace to gate. The gate is 8ft. Wide and 10 ft. Tall. How long is the brace

Answer 1

Answer:

The brace is $2\sqrt{41}$ ft ≅ 12.806 ft long

Step-by-step explanation:

The length of the diagonal of a rectangle can be found using this rule

$d=\sqrt{l^{2}+w^{2}}$ , where

• l is its length

• w is its width

∵ The gate has shaped a rectangle

∵ Its length = 10 ft

∵ Its width = 8 ft

∴ l = 10 and w = 8

∵ The brace is the diagonal

→ By using the rule above

∴ $d=\sqrt{(10)^{2}+(8)^{2}}=\sqrt{100+64}=\sqrt{164}$

∴ The length of the brace = $2\sqrt{41}$ ≅ 12.806 ft

∴ The brace is $2\sqrt{41}$ ≅ 12.806 ft long