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2 years ago

How do i solve this and what is the answer?

Mathematics

1 answer:

Alex73 [517]2 years ago

7 0

Answer:

I totally get why you are asking , how do I solve this. there is so much implied about this

Step-by-step explanation:

1st you have to recognize that ∠ACB ( in my drawing ) has that same angle as the arc from A to B , so that's implied. next you have to recognize that the triangle formed by ACB with the 124 degree angle at C is an isosceles and therefore has identical angles at A and B so that's 180 = 124 + 2A , so A = 28° and so does B , then , b/c we know that small angle... you also have to know, that the line AC is perpendicular to AD. that they from a right angle and there for... you now know , that ∠BAD is the other part of that 90 or 90= 28 + ∠BAD so ∠BAD = 62°

I went through that kinda fast, there was several "leaps" of using logic to get to the correct answer , using things you know from prior understanding about angles , circles and geometry, you are putting all of the parts together here. :/ kinda daunting in some ways.

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Which equation is the inverse of 5y+4 = (x+3)^2 + 1/2

Anna35 [415]

C. -5y -4 = -(x+3)^2 -1/2

Hope I am right.

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3 years ago

Read 2 more answers

I need help I can’t figure it out

dusya [7]

Answer:

$\large\boxed{\dfrac{41p}{70q^4(r-9)^2}}$

Step-by-step explanation:

$\dfrac{2p^4}{5q^5(r-9)^3}\cdot\dfrac{41q(r-9)}{28p^3}\\\\=\dfrac{2\!\!\!\!\diagup^1\cdot41}{5\cdot28\!\!\!\!\!\diagup_{14}}\cdot\dfrac{q\!\!\!\!\diagup}{q^{5\!\!\!\!\diagup^4}}\cdot\dfrac{(r\!\!\!\!\!\!{--}-9)\!\!\!\!\!\!{--}}{(r-9)^{3\!\!\!\!\diagup^2}}\cdot\dfrac{p^{4\!\!\!\!\diagup}}{p^3\!\!\!\!\!\!\diagup}\\\\=\dfrac{41}{70}\cdot\dfrac{1}{q^4}\cdot\dfrac{1}{(r-9)^2}\cdot\dfrac{p}{1}\\\\=\dfrac{41p}{70q^4(r-9)^2}$

7 0

2 years ago

4X Takeaway 10 equals 20+ 6X

Natasha2012 [34]

X= -15
First, we want to combine like terms.
4x-10=20+6x
Subtract 4x from both sides
-10=20+2x
Subtract 20 from both sides
-30=2x
Divide by 2 to isolate the variable
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5 0

3 years ago

Is my answer correct or no? <br> ---> show explanation & details if i am wrong!!!

neonofarm [45]

Answer:

No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle ⇒ 3rd answer

Step-by-step explanation:

From the graph of the circle

∵ The center of the circle F is at the origin

∴ F is (0 , 0)

∵ The circle passes through point (7 , 0)

- The length of the radius of the circle is the distance between

the center of the circle and a point on the circle

∴ r is the distance between points (0 , 0) and (7 , 0)

∴ $r=\sqrt{(7-0)^{2}+(0-0)^{2}}=\sqrt{49}=7$

∴ The length of the radius of the circle is 7 units

Let us find the distance between point (7 , -7) and the origin (0 , 0)

If the distance is equal to the radius of the circle, then the point is on the circle
If the distance is greater than the radius, then the point is outside the circle
If the distance is less than the radius, then the point is inside the circle

∵ The distance = $\sqrt{(7-0)^{2}+(-7-0)^{2}}=\sqrt{49+49}=\sqrt{98}=7\sqrt{2}$

∵ r = 7

∵ $7\sqrt{2}$ > 7

∴ The distance is greater than the radius of the circle

∴ Point (7 , -7) lies outside the circle

The correct answer is:

No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle

<em>Your answer is not correct, the correct answer is the 3rd answer</em>

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3 years ago

Please give Examples for real life examples for expressing very small number sin standard form.

Digiron [165]

Scientific notation is a system for expressing very large or very small numbers in a compact manner. It uses the idea that such numbers can be rewritten as a simple number multiplied by 10 raised to a certain exponent, or power.

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2 years ago