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3 years ago

Describe how to find all the points on a baseball field that are equidistant from second base and third base

Mathematics

1 answer:

BlackZzzverrR [31]3 years ago

8 0

This might help explain how to do a very similar problem.... http://www.mathopenref.com/constbisectline.html

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Write the equation of the line with a slope of 1/6 that contains (12,-7)

tatiyna

$\bf (\stackrel{x_1}{12}~,~\stackrel{y_1}{-7})~\hspace{10em} slope = m\implies \cfrac{1}{6} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-7)=\cfrac{1}{6}(x-12) \\\\\\ y+7=\cfrac{1}{6}x-2\implies y=\cfrac{1}{6}x-9$

6 0

3 years ago

Read 2 more answers

Jed wants to earn 25% annual net income on his $50,000 cash investment in property his annual expense of owning the property are

Elena L [17]

Answer: $1,842

Step-by-step explanation:

John wants to earn 25% of his investment of $50,000 which is:

= 25% * 50,000

= $12,500

He has expenses of $9,600 yearly so the rent he should charge per year in order to make his 25% requirement as income is:

= Expenses + Return

= 9,600 + 12,500

= $22,100

Rent per month is:

= 22,100 / 12

= $1,842

8 0

3 years ago

PLZ HELP ASAP WILL MARK BRAINLIEST

Mkey [24]

DEF will be 2.68

EF will be .67

3 0

3 years ago

Improper fracations

NemiM [27]

Answer:

64+77=141

Step-by-step explanation:

The whole number times the denominator plus the numerator. Then, add and do the same thing again with the other number and you get 64 and 77 then add and you get 141

5 0

3 years ago

Susan threw a softball 42 years on her first try and 51 1/3 yard on her second try. How much farther did she throw the softball

Andru [333]

Answer:

28 feet farther than 1st ball.

Step-by-step explanation:

We have been given that Susan threw a softball 42 yards on her first try and $51\frac{1}{3}$ yard on her second try.

To find second ball is how much farther from the 1st ball, we will subtract 42 yards from $51\frac{1}{3}$ yards.

$\text{The second ball is farther from 1st ball}=51\frac{1}{3}\text{ yards}-42\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-42\text{ yards}$

Let us have a common denominator.

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{42*3}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{126}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154-126}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{28}{3}\text{ yards}$

$\text{1 yard}=3\text{ feet}$

$\frac{28}{3}\text{ yards}=\frac{28}{3}\times 3\text{ feet}$

$\frac{28}{3}\text{ yards}=28\text{ feet}$

Therefore, Susan thrown the second ball 28 feet farther from the 1st ball.

7 0

4 years ago