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Svetlanka [38]
3 years ago
14

What is the volume of this cone?

Mathematics
1 answer:
dlinn [17]3 years ago
3 0

Answer:

167.46

Step-by-step explanation:

V=\frac{1}{3} X  \pi r^{2} X h

\frac{1}{3} x  3.14 x 4^{2} x10

\frac{1}{3} X 50.24x 10

\frac{1}{3} x 502.4

V=167.46

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$(x) = -22 +22. - 114
galina1969 [7]

Answer:

a

Step-by-step explanation:

5 0
3 years ago
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Plz help ASAP number 4 I️ have B and 7 I️ have c plz help with the rest
Veronika [31]

Answer:

5 is interpolation

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4 0
3 years ago
A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex
Roman55 [17]

Answer:

 Standard error (S.E) =  0.048  ≅ 0.05

Step-by-step explanation:

<u>Explanation</u>:-

Given  sample size 'n'=76

Given the dean who randomly selects 76 students and finds that 58 out of 76 are receiving financial aid.

Sample proportion

                         p = \frac{x}{n} = \frac{58}{76} = 0.7631

The standard error is determined by

                     S.E = \sqrt{\frac{p(1-p)}{n} }

                     S.E = \sqrt{\frac{0.763(0.2369}{76} }

  Standard error is 0.048  ≅ 0.05

3 0
3 years ago
A bacteria culture begins with 15 bacteria which double in amount at the end of every hour. How many bacteria are grown during t
elixir [45]
We use P = i•e^rt for exponential population growth, where P = end population, i = initial population, r = rate, and t = time
P = 2•i = 2•15 = 30, so 30 = 15 [e^(r•1)],
or 30/15 = 2 = e^(r)
ln 2 = ln (e^r)
.693 = r•(ln e), ln e = 1, so r = .693
Now that we have our doubling rate of .693, we can use that r and our t as the 12th hour is t=11, because there are 11 more hours at the end of that first hour
So our initial population is again 15, and P = i•e^rt
P = 15•e^(.693×11) = 15•e^(7.624)
P = 15•2046.94 = 30,704
4 0
3 years ago
Read 2 more answers
The parents' club will need 100 of the same item for international night. They have a budget of $250. The choices are 100 baseba
Nuetrik [128]

Answer:

The parents' club can afford to buy 100 Baseball hats or 100 sports bottles.

Step-by-step explanation:

Given:

Item to be bought = 100

Total Budget = $250

Cost of each Baseball Hat = $2.45

Cost of each sports bottles = $2.50

Cost of each flag = $2.75

We need to find which items can they afford to buy.

Solution:

each Baseball Hat = $2.45

100 Baseball Hat = Cost of 100 Baseball Hat

Using Unitary method we get;

Cost of 100 Baseball Hat  = 2.45\times 100 =\$245

each sports bottles = $2.50

100 sports bottles = Cost of 100 sports bottles

Using Unitary method we get;

Cost of 100 sports bottles  = 2.5\times 100 =\$250

each flag = $2.75

100 flags = Cost of 100 flags

Using Unitary method we get;

Cost of 100 flags  = 2.75\times 100 =\$275

Hence from above we can see that;

Cost of 100 Base ball hat and 100 sports bottles are within the budget while Cost of 100 flags exceed the budget.

So we can say that;

The parents' club can afford to buy 100 Baseball hats or 100 sports bottles.

6 0
3 years ago
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