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olganol [36]
3 years ago
8

Show (with tens and hundreds) how to count from 60 to 430

Mathematics
1 answer:
Rzqust [24]3 years ago
8 0

Answer:

three groups of 100 and 7 groups of 10

Step-by-step explanation:

430-60=370

370=3x100 + 7x10

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The length of a rectangle is 55 inches more than the width. the perimeter is 4242 inches. find the length and the width of the r
faust18 [17]
L = W + 55
2L + 2W = 4242

L + W = 2121
(W + 55) + W = 2121
2W + 55 = 2121

W = 1033 inches           L = 1088 inches
6 0
2 years ago
An isosceles trapezoid has base angles of 45° and bases of lengths 8 and 14. The area of the trapezoid is
tigry1 [53]
You forgot to add in your height to your question. To find your area you need to do 8 + 14 and get 22 then you nee to do the height divided by two. If you give me the height of the triangle I can tell you the area.
8 0
2 years ago
Which is equivalent
arlik [135]

Answer:

D  8√(10) ^3x

Step-by-step explanation:

We have

sqrt(10) ^ (3/4x)

We can rewrite the sqrt as ^1/2

10 ^ (1/2) ^ (3/4x)

We know that a^b^c = a^(b*c)

10 ^(1/2 *3/4x)

10 ^(3/8 x)

The numerator is the power

The denominator is the root

8√(10) ^3x

8 0
3 years ago
What is 7/8 plus 1/3
horsena [70]
7/8 +1/3 =1 1/8 that is the answer

5 0
3 years ago
Write the point slope form of the line that passes through (-8,2) and is parallel to a line with a slope of -8. include all your
Juli2301 [7.4K]

<u>Answer: </u>

The point slope form of the line that passes through (-8,2) and is parallel to a line with a slope of -8 is 8x + y + 62 = 0

<u>Solution: </u>

The point slope form of the line that passes through the points \left(x_{1} y_{1}\right) and parallel to the line with slope “m” is given as  

y-y_{1}=m\left(x-x_{1}\right) --- eqn 1

Where “m” is the slope of the line.  

x_{1} \text { and } y_{1} are the points that passes through the line.

From question, given that slope “m” = -8

Given that the line passes through the points (-8,2).Hence we get

x_{1}=-8 ; y_{1}=2

By substituting the values in eqn 1, we get the point slope form of the line which is parallel to the line having slope -8 can be found out.

y-2=-8(x-(-8))

On simplifying we get

y – 2 = -8(x +8)

y – 2 = -8x -64

y – 2 +8x +64 = 0

8x + y +62 = 0

Hence the point slope form of given line is 8x + y +62 = 0

7 0
2 years ago
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