Find the result of 3(a−b−c)+a−bb−c; if a = -1, b = 1, and c = -3.<br> WITH PROCEDURE PLEASE

use an equation to write each fraction as multiple of unit fraction 1/6 + 1/6 + 1/6 + 1/6 + 1/6 how do you get to 5/6

weeeeeb [17]

Answer:

Equation: 1/6 + 1/6 + 1/6 + 1/6 + 1/6 = 5/6

Step-by-step explanation:

Unit means 1

Therefore a each 1/6 is the multiple unit of 5/6 because if we had all the 1/6 together, you get 5/6. There is 1 over 6 which you can tell that it is a unit fraction.

8 0

3 years ago

Fifteen equals s over thirteen

zimovet [89]

Can you restate the question please

6 0

3 years ago

HELP NOW PLEASE ASAP!!

algol [13]

Answer:

The answer is D, your welcome

4 0

3 years ago

Read 2 more answers

2. Check the boxes for the following sets that are closed under the given

son4ous [18]

The properties of the mathematical sequence allow us to find that the recurrence term is 1 and the operation for each sequence is

a) Subtraction

b) Addition

c) AdditionSum

d) in this case we have two possibilities

* If we move to the right the addition

* If we move to the left the subtraction

The sequence is a set of elements arranged one after another related by some mathematical relationship. The elements of the sequence are called terms.

The sequences shown can be defined by recurrence relations.

Let's analyze each sequence shown, the ellipsis indicates where the sequence advances.

a) ... -7, -6, -5, -4, -3

We can observe that each term has a difference of one unit; if we subtract 1 from the term to the right, we obtain the following term

-3 -1 = -4

-4 -1 = -5

-7 -1 = -8

Therefore the mathematical operation is the subtraction.

b) $0. \sqrt{1}. \sqrt{4}, \sqrt{9}, \sqrt{16}, \sqrt{25}$ ...

In this case we can see more clearly the sequence when writing in this way

$0, \sqrt{1^2}. \sqrt{2^2}, \sqrt{3^2 } . \sqrt{4^2} , \sqrt{5^2}$

each term is found by adding 1 to the current term,

$\sqrt{(0+1)^2} = \sqrt{1^2} \\\sqrt{(1+1)^2} = \sqrt{2^2}\\\sqrt{(2+1)^2} = \sqrt{3^2}\\\sqrt{(5+1)^2} = \sqrt{6^2}$

Therefore the mathematical operation is the addition

c) $... \frac{-10}{2}. \frac{-8}{2}, \frac{-6}{2}, \frac{-4}{2}. \frac{-2}{2}. ...$

The recurrence term is unity, with the fact that the sequence extends to the right and to the left the operation is

To move to the right add 1

- $\frac{-10}{2} + 1 = \frac{-10}{2} - \frac{2}{2} = \frac{-8}{2}\\\frac{-8}{2} + \frac{2}{2} = \frac{-6}{2}$

To move left subtract 1

$\frac{-2}{2} - 1 = \frac{-4}{2}\\\frac{-4}{2} - \frac{2}{2} = \frac{-6}{2}$

Using the properties the mathematical sequence we find that the recurrence term is 1 and the operation for each sequence is

a) Subtraction

b) Sum

c) Sum

d) This case we have two possibilities

If we move to the right the sum

If we move to the left we subtract

Learn more here: brainly.com/question/4626313

5 0

3 years ago

Ayudaaa es urgente por favor :(

rjkz [21]

3 /24 porque es 1/12

7 0

3 years ago

Find the result of 3(a−b−c)+a−bb−c; if a = -1, b = 1, and c = -3. WITH PROCEDURE PLEASE