5= 3 1 (x+7) ) x = <br> What is it?

Zoey is 346 meters below sea level while visiting a part of Israel. She descends 71 meters to visit the Dead Sea. Which integer

ZanzabumX [31]

Thanks but you have to at the negative sign so it should look like this -275 not just 275 and 275 without the negative integer is not even a answer so the correct answer is -275

4 0

4 years ago

Express as a trinomial.<br> (x + 1)(3x − 2)<br> PLEASE HELP :)

Free_Kalibri [48]

Answer:

3x^2+x-2

Step-by-step explanation:

7 0

3 years ago

I don’t know how to solve this

V125BC [204]

Assuming that both triangles are an exact copy of one another, it is safe to assume that 3y-7 is equal to 41. Set up an equation

3y-7=41

Add 7 to both sides

3y=48

Divide both sides by 3

y=16

Now to find PN.

Based on what we know, we can assume that MP = PN. Let's make some equations!

MP = 17x-8 PN = 11x+4

17x-8 = 11x+4

Subtract 11x from both sides

6x-8 = 4

Add 8 to both sides

6x = 12

Divide by 2

x=2

Substitute 2 in for x in the equation for PN

11(2)+4

Multiply 11 by 2

22+4 = 26

PN = 26

7 0

3 years ago

Please answer with the correct answer<br> will mark as brainyest if you get the right answer

9966 [12]

Okay, for the first part, you just add it all together. So 7x+19x+9+18. For the second part, just combine like terms. So you would get 26x+27.

4 0

3 years ago

Read 2 more answers

The average length of a field goal in the National Football League is 38.4 yards, and the s. d. is 5.4 yards. Suppose a typical

Tasya [4]

Answer:

a) The sample is larger than 30, so, by the Central Limit Theorem, the distribution of the sample means will be normally distributed with mean 38.4 and standard deviation 0.8538.

b) 0.25% probability that his average kicks is less than 36 yards

c) 0.11% probability that his average kicks is more than 41 yards

d-a) The sample is larger than 30, so, by the Central Limit Theorem, the distribution of the sample means will be normally distributed with mean 38.4 and standard deviation 1.08

d-b) 1.32% probability that his average kicks is less than 36 yards

d-c) 0.80% probability that his average kicks is more than 41 yards

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$\mu = 38.4, \sigma = 5.4, n = 40, s = \frac{5.4}{\sqrt{40}} = 0.8538$

a. What is the distribution of the sample mean? Why?

The sample is larger than 30, so, by the Central Limit Theorem, the distribution of the sample means will be normally distributed with mean 38.4 and standard deviation 0.8538.

b. What is the probability that his average kicks is less than 36 yards?

This is the pvalue of Z when X = 36. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{36 - 38.4}{0.8538}$

$Z = -2.81$

$Z = -2.81$ has a pvalue of 0.0025

0.25% probability that his average kicks is less than 36 yards

c. What is the probability that his average kicks is more than 41 yards?

This is 1 subtracted by the pvalue of Z when X = 41. So

$Z = \frac{X - \mu}{s}$

$Z = \frac{41 - 38.4}{0.8538}$

$Z = 3.05$

$Z = 3.05$ has a pvalue of 0.9989

1 - 0.9989 = 0.0011

0.11% probability that his average kicks is more than 41 yards

d. If the sample size is 25 in the above problem, what will be your answer to part (a) , (b)and (c)?

Now $n = 25, s = \frac{5.4}{\sqrt{25}} = 1.08$

So

a)

The sample is larger than 30, so, by the Central Limit Theorem, the distribution of the sample means will be normally distributed with mean 38.4 and standard deviation 1.08

b)

$Z = \frac{X - \mu}{s}$

$Z = \frac{36 - 38.4}{1.08}$