What is the range of this relation?

Mathematics

1 answer:

riadik2000 [5.3K]2 years ago

5 0

The range of the relation is 35,40,45,60,75
Reason being in relation range is the set of all second elements of ordered pairs (y-coordinates).

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3x - 2y + 3z = -20 4x - 3y - 2z = 7 -5x + 5y + z = 9

skelet666 [1.2K]

Answer:

x= 4 y= 7 z= -6

Step-by-step explanation:

solve for one and you get them all

First, I got rid of the z by multiplying common factors (multiplied z by 2) and added equations 2 and 3 together after multiplying by 2

4x - 3y - 2z = 7

-10x+10y+2z= 18

-6x+7y= 25

Then multiplied z by -3 (to get rid of the z) with the original equation 3

3x - 2y + 3z = -20

15x-15y-3z= -27

18x-17y= -47

Next find common thing between the 2 equations we got and multiply it by that and combine (we can multiply first equation by 3 to get rid of the x and solve for y)

-18x+21y= 75

18x-17y= -47

y=7

Work backwards, substitute 7 into the above equation, you get x= 4 and then same for z to get z= -6

8 0

2 years ago

what is the distance between point S and U? Round to the nearest tenth of a unit? A 3.3 B 6.4 C 8.1 D 12.0

ki77a [65]

The distance between the points (d) is found using the Pythagorean theorem.

Imagine the two points as defining the hypotenuse of a right triangle. The lengths of the legs of the triangle are the horizontal distance between the points and the vertical distance between the points. The the theorem tells us
d² = 4² + 7²
d² = 16 + 49
d² = 65
d = √65 ≈ 8.1

The distance between the points is
C 8.1

_____
You know that the distance must be longer than the longest leg (7) and must be shorter than the sum of the two legs (4+7=11). The only answer choice between 7 and 11 is 8.1.