3 years ago

Please help I don’t understand

Mathematics

1 answer:

madam [21]3 years ago

3 0

I don’t get it either

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What is the amplitude of the cosine function corresponding to the secant function graphed below ? a. -2 b. -1 c. 2 d. 3

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Answer:

Step-by-step explanation:

From the graph, we obtain the trigonometric function as:

$y=2 \sec x+1$

The corresponding cosine function have equation.

$y=2\cos x+ 1$

This function is of the form: $y=a\cos bx+c$

where $|a|$ is the amplitude.

Therefore the amplitude is |2|=2

The third choice is correct

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3 years ago

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Answer: 3

Step-by-step explanation:

7-3+4-2+9=15

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3 years ago

Prove the trigonometric identity

Annette [7]

Answer:

Proved See below

Step-by-step explanation:

Man this one is a world of its own :D Just a quick question are you a fellow Add Math student in O levels i remember this question from back in the day :D Anyhow Lets get started

For this question we need to know the following identities:

$1+tan^{2}x=sec^2x\\\\1+cot^2x=cosec^2x\\\\sin^2x+cos^2x=1$

Lets solve the bottom most part first:

$1-\frac{1}{1-sec^2x} \\\\$

Take LCM

$1-\frac{1}{1-sec^2x} \\\\\frac{1-sec^2x-1}{1-sec^2x} \\\\\frac{-sec^2x}{1-sec^2x} \\\\\frac{-(1+tan^2x)}{-tan^2x}$

now break the LCM

$\frac{-1}{-tan^2x}+\frac{-tan^2x}{-tan^2x}\\\\\frac{1}{tan^2x}+1\\\\cot^2x+1$

because 1/tan = cot x

and furthermore,

$cot^2x+1\\cosec^2x$

now we solve the above part and replace the bottom most part that we solved with $cosec^2x$

$\frac{1}{1-\frac{1}{cosec^2x} } \\\\\frac{1}{1-sin^2x} \\\\\frac{1}{cos^2x}\\\\sec^2x$

Hence proved! :D

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3 years ago

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ss7ja [257]

Answer:

900

Step-by-step explanation:

$90 * 10$
$900$

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