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Ulleksa [173]
3 years ago
8

Why would a team choose to employ a zone defense over a person to person defense?

Computers and Technology
1 answer:
vova2212 [387]3 years ago
7 0

Answer/Explanation:

Zone defense is chosen if MULTIPLE people are attacking one spot that's why they would choose zone defense.

Person to person defense is when 1 person is attacking one spot so somebodies sent out to defend it.

<u><em>~ LadyBrain</em></u>

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If you have different movie or audio file types saved to your computer and your computer can only play the OGG format instead of
galina1969 [7]

Answer:

convert the MP4 format file to the OGG format file                  

Explanation:        

An OGG file is a compressed audio file of Ogg Vorbis that is used for holding audio data. It is a free and an open container file format which is maintained by Xiph.Org Foundation. OGG format file can multiplex independent streams of video, text, audio and meta data.

The OGG file has better sound quality and characteristics than a MP3 or MP4 files. The MP4 file format can be converted into OGG format file if the files are saved in different formats in the computer which can play only OGG format.

5 0
2 years ago
The battery indicator light is on, even though your laptop is plugged into the AC adaptor. To determine why you are not getting
Natasha2012 [34]

Answer:

D. All of the above

Explanation:

When the laptop of the battery is low it shows a red light specifies that the battery of the laptop is low but the laptop charger is plugged into the Ac adapter still the power is not getting from the Ac adapter so we should check whether the AC adapter is properly connected to the laptop or not,  whether the ac adapter is plugged to a live electric outlet or not or whether the DC jack is loose or not.

In overall, we have to check all the given conditions mentioned in the question

6 0
2 years ago
Read 2 more answers
Can someone tell me 5 facts about Registers and RAM, please?
Maslowich

\int\limits^a_b {x} \, dx \left \{ {{y=2} \atop {x=2}} \right.  \lim_{n \to \infty} a_n \neq \neq \geqAnswer:

A register is a temporary storage area built into a CPU. ... The instruction register fetches instructions from the program counter (PC) and holds each instruction as it is executed by the processor. The memory registers are used to pass data from memory to the processor.

PLS MARK BRAINLIEST!!!

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3 0
2 years ago
This lesson introduced the notion of "efficiency" in programming, and that it might mean different things at different times. Th
Morgarella [4.7K]

Answer:

<u>In physics</u>, efficiency is a measure of how much energy is conserved in a process.

<u>In programming</u>, efficiency is directly linked with the speed of runtime execution for software and algorithmic efficiency.

In this comparison, both meanings try to measure the quality of the processes and have formulas to detect this efficiency.

Both meanings have different formulas to define the measures, Big O notation for programming and percentage of energy output divided by energy input for physics. Furthermore, in physics is not possible to get 100% efficiency, but it is possible for programming to have O(1) of efficiency.

4 0
2 years ago
Write a program that lets the user enter the total rainfall for each of 12 months (starting with January) into an array of doubl
lianna [129]

Answer:

The C++ code is given below with appropriate comments

Explanation:

#include "stdafx.h"

//Header file section

#include <iostream>

#include <iomanip>

#include <string>

using namespace std;

//Function prototypes

double rainfallTotal(double[], int);

double averageMonthlyRainfall(double[], int);

double highestAmountRainfall(double[], int, int &);

double lowestAmountRainfall(double[], int, int &);

int main()

{

//Initialize variables

const int ALL_MONTHS = 12;

int highIndex = 0;

int lowIndex = 0;

//Declare variables

double totalRf;

double averageRf;

double mostRf;

double leastRf;

double monthlyRf[ALL_MONTHS];

string monthName[ALL_MONTHS] = { "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December" };

for (int i = 0; i < ALL_MONTHS; i++)

{

 cout << "Enter rainfall for " << monthName[i] << ": ";

 cin >> monthlyRf[i];

 // Check the input as negative numbers

 //for monthly rainfall

 while (monthlyRf[i] < 0)

 {

  cout << "Invalid data (negative rainfall) " << endl;

  cout << "Retry the rainfall in " << monthName[i] << ": ";

  cin >> monthlyRf[i];

 }

}

//Call the methods

totalRf = rainfallTotal(monthlyRf, ALL_MONTHS);

averageRf = averageMonthlyRainfall(monthlyRf, ALL_MONTHS);

mostRf = highestAmountRainfall(monthlyRf, ALL_MONTHS, highIndex);

leastRf = lowestAmountRainfall(monthlyRf, ALL_MONTHS, lowIndex);

//Display output

cout << fixed << showpoint << setprecision(2) << endl;

cout << "Total rainfall: " << totalRf << endl;

cout << "Average rainfall: " << averageRf << endl;

cout << "Least rainfall in " << monthName[lowIndex] <<endl;

cout << "Most rainfall in " << monthName[highIndex] <<endl;

system("pause");

return 0;

}

//Method definition of rainfallTotal

double rainfallTotal(double totalRainfall[], int n)

{

double total = 0;

for (int i = 0; i < n; i++)

 total += totalRainfall[i];

return total;

}

//Method definition of averageMonthlyRainfall

double averageMonthlyRainfall(double totalRainfall[], int n)

{

double average = 0.0;

double total = 0;

for (int i = 0; i < n; i++)

 total += totalRainfall[i];

average = total / n;

return average;

}

//Method definition of lowestAmountRainfall

double lowestAmountRainfall(double totalRainfall[], int n, int &monthIndex)

{

double least;

int i = 0;

least = totalRainfall[i];

while (i < n)

{

 if (totalRainfall[i] < least)

 {

  least = totalRainfall[i];

  monthIndex = i;

 }

 i++;

}

return least;

}

//Method definition of highestAmountRainfall

double highestAmountRainfall(double totalRainfall[], int n, int &monthIndex)

{

double high;

int i = 0;

high = totalRainfall[i];

while (i < n)

{

 if (totalRainfall[i] > high)

 {

  high = totalRainfall[i];

  monthIndex = i;

 }

 i++;

}

return high;

}

3 0
2 years ago
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