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3 years ago

Find the answer for the question please..

Mathematics

2 answers:

Gnesinka [82]3 years ago

8 0

Answer:

44 scoops

Step-by-step explanation:

create a proportion of amt of choc syrup to # scoops

1/16 ÷ 1 = 11/4 ÷ s

cross-multiply to get:

s = 16 x 11/4

s = 44 scoops

DaniilM [7]3 years ago

7 0

Answer:

Step-by-step explanation:

3/4×16=12

12+16(2)=44

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Evaluate the expression <br><br> x=-4.9 and y=-1.3 <br><br> -5x+7y

Flura [38]

Answer:

15.4

Step-by-step explanation:

-5×(-4.9) +7×(-1.3)

=24.5+(-9.1)

=24.5-9.1

==15.4

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2 years ago

Factorise them please

Shalnov [3]

Answer:

2x+10 = 2(x+5)

5x-15 = 5(x-3)

8x+6 = 2(4x+3)

12x-8 = 4(3x-2)

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Step-by-step explanation:

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2 years ago

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Elena runs for 28 seconds and finishes at 250 seconds what is her velocity please explain

ExtremeBDS [4]

Answer:

The velocity is 8.93 meters/second.

Step-by-step explanation:

It is given that Elena runs for 28 seconds and finishes at 250 meters.

Here the displacement is 250 meters and the time is 28 seconds.

We know that $V=\dfrac{\text{Displacement}}{\text{Time}}$

Substitute displacement = 250 and time = 28 in above formula.

$V=\dfrac{250}{28}$

$V\approx 8.93$ meters/second

Hence, the velocity is 8.93 meters/second.

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3 years ago

State. Probability sampling vs. non probability sampling

Savatey [412]

Probability sampling simply illustrates a scenario where the subjects of the population have an equal opportunity.

<h3>What is probability sampling?</h3>

Probability simply means the likelihood of the occurence of an event.

In this case, in probability sampling, the subjects of the population have an equal opportunity.

In non-sampling, an equal opportunity isn't given.

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1 year ago

How do I differentiate this?

disa [49]

Answer:

$\frac{8}{\left(-x+2\right)^2}$ & $x = 1, x = 3$

Step-by-step explanation:

I'm sure you are familiar with the product rule,

If y = u*v => dy/dx = u * dv/dx + v * dy/dx <----- product rule

In this case:

$u=3x+2,\:v=\left(2-x\right)^{-1},\\=>\frac{d}{dx}\left(3x+2\right)\left(2-x\right)^{-1}+\frac{d}{dx}\left(\left(2-x\right)^{-1}\right)\left(3x+2\right)$

Now remember the sum rule:

$\frac{d}{dx}\left(3x+2\right) = \frac{d}{dx}\left(3x\right)+\frac{d}{dx}\left(2\right),\\\frac{d}{dx}\left(3x\right) = 3,\\\frac{d}{dx}\left(2\right) = 0\\\frac{d}{dx}\left(3x+2\right) = 3$

For this second bit we apply the chain rule:

$\frac{d}{dx}\left(\left(2-x\right)^{-1}\right) = -\frac{1}{\left(2-x\right)^2}\frac{d}{dx}\left(2-x\right),\\\frac{d}{dx}\left(2-x\right) = -1,\\\\=> -\frac{1}{\left(2-x\right)^2}\left(-1\right)\\=> \frac{1}{\left(2-x\right)^2}$

If we substitute these values back into the expression... $\frac{d}{dx}\left(3x+2\right)\left(2-x\right)^{-1}+\frac{d}{dx}\left(\left(2-x\right)^{-1}\right)\left(3x+2\right)$

...we get the following:

$3\left(2-x\right)^{-1}+\frac{1}{\left(2-x\right)^2}\left(3x+2\right)$

The rest is just pure simplification:

$3\left(2-x\right)^{-1}+\frac{1}{\left(2-x\right)^2}\left(3x+2\right)\\= \frac{3}{-x+2}+\frac{3x+2}{\left(-x+2\right)^2}\\= \frac{3\left(-x+2\right)}{\left(-x+2\right)^2}+\frac{3x+2}{\left(-x+2\right)^2}\\\\= \frac{3\left(-x+2\right)+3x+2}{\left(-x+2\right)^2}\\\\= \frac{8}{\left(-x+2\right)^2}$

Now let's equate this to equal 8 for the second bit and solve for x:

$\frac{8}{\left(-x+2\right)^2}=8,\\\frac{8}{\left(-x+2\right)^2}\left(-x+2\right)^2=8\left(-x+2\right)^2,\\8=8\left(-x+2\right)^2,\\\left(-x+2\right)^2=1,\\x = 1, x = 3$

4 0

2 years ago