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joja [24]
3 years ago
6

Find the answer for the question please..

Mathematics
2 answers:
Gnesinka [82]3 years ago
8 0

Answer:

44 scoops

Step-by-step explanation:

create a proportion of amt of choc syrup to # scoops

1/16 ÷ 1 = 11/4 ÷ s

cross-multiply to get:

s = 16 x 11/4

s = 44 scoops

DaniilM [7]3 years ago
7 0

Answer:

44

Step-by-step explanation:

3/4×16=12

12+16(2)=44

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xxTIMURxx [149]

Step-by-step explanation:

-\sqrt5-3\sqrt5=-1\sqrt5-3\sqrt5=(-1-3)\sqrt5=-4\sqrt5

3 0
4 years ago
I need help with this one and l also answered the first one but i’m not sure for this three angles
Norma-Jean [14]

Answer:

all three angles should add up to 180 so subtract what you know from 180 and you should be able to find everything from there

4 0
3 years ago
. The larger of two numbers is 7 less than twice the
Ganezh [65]

Answer:

x = 2y - 7

x + y = 47

substitute x

2y - 7 + y = 47

3y = 54

y = 18

x = 2x18 - 7

x = 29

4 0
3 years ago
Picture picture picture
cluponka [151]
Soo what do you need help with? It seems pretty easy. I can help you if you want.
6 0
3 years ago
Read 2 more answers
A simple random sample of 110 analog circuits is obtained at random from an ongoing production process in which 20% of all circu
telo118 [61]

Answer:

64.56% probability that between 17 and 25 circuits in the sample are defective.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 110, p = 0.2

So

\mu = E(X) = np = 110*0.2 = 22

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{110*0.2*0.8} = 4.1952

Probability that between 17 and 25 circuits in the sample are defective.

This is the pvalue of Z when X = 25 subtrated by the pvalue of Z when X = 17. So

X = 25

Z = \frac{X - \mu}{\sigma}

Z = \frac{25 - 22}{4.1952}

Z = 0.715

Z = 0.715 has a pvalue of 0.7626.

X = 17

Z = \frac{X - \mu}{\sigma}

Z = \frac{17 - 22}{4.1952}

Z = -1.19

Z = -1.19 has a pvalue of 0.1170.

0.7626 - 0.1170 = 0.6456

64.56% probability that between 17 and 25 circuits in the sample are defective.

4 0
3 years ago
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