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alexira [117]
2 years ago
8

HELP ASAP!! Which representation shows y as a function of x ?

Mathematics
1 answer:
Marat540 [252]2 years ago
6 0

Answer:

It is the first answer

Step-by-step explanation:

For it to be considered a function, each x-value can only corresponds (have) one y-value, however, y-values (even if they are the same y-value) can have multiple different x-values.

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Please help me with this!!
Naddik [55]

Step-by-step explanation:

To find the y-coordinate points we need to evaluate the function for all the x values in the table. In other words, we need to replace x with each value in our given function and simplify.

- For x = 0

f(x)=(x-2)^2-5

f(0)=(0-2)^2-5

f(0)=(-2)^2-5

f(0)=4-5

f(x)=-1

Since x=0 and y=-1, our first point is (0, -1)

- For x = 1

f(x)=(x-2)^2-5

f(1)=(1-2)^2-5

f(1)=(-1)^2-5

f(1)=1-5

f(x)=-4

Our second point is (1, -4)

- For x = 2

f(x)=(x-2)^2-5

f(2)=(2-2)^2-5

f(2)=(0)^2-5

f(x)=-5

Our third point is (2, -5)

- For x = 3

f(x)=(x-2)^2-5

f(3)=(3-2)^2-5

f(3)=(1)^2-5

f(3)=1-5

f(x)=-4

Our fourth point is (3, -4)

- For x = 4

f(x)=(x-2)^2-5

f(4)=(4-2)^2-5

f(4)=(2)^2-5

f(4)=4-5

f(x)=-1

Our fifth point is (4, -1)

Now we just need to plot each point in our coordinate plane and join them with the parabola as you can see in the attached picture.

3 0
2 years ago
Expand and simplify 6(2x - 3) – 2(2x + 1)
Charra [1.4K]

Answer 8x - 20

Step-by-step explanation:

6(2x - 3) - 2(2x + 1)

Distribute

6(2x) -6( 3) - 2(2x) -2( 1)

12x -18 -4x -2

Combine like terms

12x -4x    -18 -2

8x-20

3 0
3 years ago
Simplify the decimal 15.1851851852
luda_lava [24]
The answer is to the thousands 15.185 to the hundredth is 15.19
6 0
3 years ago
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The weight of an object on the moon is 1/6 its weight on earth. If a bowling ball weighs 12 and 1/2 pounds on earth, how much do
cluponka [151]
(12½) ÷ (⅙) = (25/2) ÷ (⅙) = (25/2) × (6/1) =75
3 0
2 years ago
Error analysis: describe and correct the error in solving the equation.
maw [93]
The only solution of the equation is x=0
8 0
2 years ago
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